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What is 6n plus 3 equals 15?
6n+3=15 6n+3-3=15-3=12 6n = 12 n=12/6 = 2
In this algebraic expression what is the 3 called 6n plus 3?
3 is called the constant term and the 6n is called the linear term.
What is the solution to 6n-4-3 equals 3n plus 10 plus 4n?
6n - 4 - 3 = 3n + 10 + 4n -7 = 7n - 6n + 10 -17 = n
What is the variable for 6n plus 3?
In the expression 6n+3 the variable or the unknown is n
What is the constant in this algebraic expression 6n plus 3?
It is: 3
What is 6n plus 3 equals 15?
6n+3=15 6n+3-3=15-3=12 6n = 12 n=12/6 = 2
What is 6n divided bu 10 equals 3?
6n/10=3 6n=30 n=5
What is 6n-3 equals 2n plus 9?
6n -3=2n+9 6n-2n=9+3 4n=12 n=12/4 n=3
What is the variable in this algebraic expression of 6n 3?
The unknown variable in the expression: 6n+3 is n
5n plus 3 equals 14-6n what is n?
5n + 3 = 14 - 6n <=> 5n +6n = 14 - 3 <=> 11n = 11 => n = 11/11 = 1
What is the coefficient in 6n 3?
6 is the coefficient, n is the variable, 3 is the constant
What is 5 over 2n plus 3 over 3n?
15/6n + 6/6n = 21/6n = 7/2n
How do you evaluate 6n plus 4 and 6n plus 4 for n3?
I assume that you mean n = 3 6n + 4 = 6(3) + 4 = 18 + 4 = 22
In this algebraic expression what is the 3 called 6n plus 3?
3 is called the constant term and the 6n is called the linear term.
What is -6n 2?
-6n = 2 can be simplified giving the value of n as -1/3.
Why all non prime number are divisible by 2 or 3 or 6 times n plus 1 or 6 times n minus 1?
All non-prime numbers are divisible by prime numbers. Now the smallest to prime numbers are 2 and 3. The next prime number is 5, which is 6*1 - 1. All larger numbers are in the form of one of 6n, 6n+1, 6n+2, 6n+3, 6n+4, 6n+5. Now 6n is divisible by 2 and so cannot be a prime. 6n+2 and 6n+4 are also divisible by 2 and so cannot be prime. 6n+3 is divisible by 3 and so cannot be prime. That leave 6n+1 and 6n+5 as the only two forms than can be prime. Note though that 6n+5 = 6m-1 where m = n+1. So all primes are of the form 2, 3, 6n+1 and 6n-1. And all primes can be divided by primes. The result follows.
Is there a pattern for prime numbers?
So far, the best and most general pattern found is that, over three, all prime numbers are of the form 6n +/- 1. In other words, they're either 6n - 1 or 6n + 1, for some n. Here is why this is true. We could do a proof by contradiction and assume that all the natural numbers greater than or equal to 5 are prime. (of course they are not!) We start with5 which is 6-1. The numbers would then be 6n - 1, 6n, 6n + 1, 6n + 2, 6n + 3, 6n + 4, and 6n + 5 for some natural number n. If it is 6n, then the number is divisible by 6. When it is 6n + 2, the number is the same as 2(3n+1) so it is divisible by 2. Consider 6n + 3, the number is 3(2n+1), so it is divisible by 3. Last look at 6n + 4, the number is divisible by 2, for it's 2(3n + 2). Therefore all numbers of the form 6n, 6n + 2, 6n + 3, and 6n + 4 are not prime. The only possibilities this leaves are 6n - 1 and 6n + 1. This entire thing can be written more elegantly with congruences, but the goal here was simplicity! There are many other patterns in primes. See the attached link to see them.
