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11x + 2
2x + 9 = 6x + 1 9 - 1 = 6x - 2x 8 = 4x x = 2
Let 6x - 2x - 9 = a, where a is an arbitrary constant. Then 4x - 9 = a 4x = a+9 x = (a+9)/4
4x2 + 6x - 3 (with no remainder)
x2 - 6x - 27 = (x-9)(x+3)