73
Roman numerals:IX*IX = LXXXILXXXI/III = XXVIIXXVII+LXXIII = LXXXXVIIIII => CArabic numerals:9*9 = 8181/3 = 2727+73 = 100
73% of 73 = 73% * 73 = 0.73 * 73 = 53.29
9x squared-15x squared = -6
73= 73/1
73
c= sq rt of 73
* a2 + b2 = c2 * a = 3 * b = 8 * (3)2 + (8)2 = c2 * 9 + 64 = c2 * 73 = c2 * c = √73
Roman numerals:IX*IX = LXXXILXXXI/III = XXVIIXXVII+LXXIII = LXXXXVIIIII => CArabic numerals:9*9 = 8181/3 = 2727+73 = 100
The two square numbers that make 73 are 64 (8^2) and 9 (3^2). To find this, you can start by taking the square root of 73, which is approximately 8.544. The closest square numbers to this are 64 and 81, with 64 being the square of 8 and 81 being the square of 9.
Call the angle v: tan v = opp/ adj = 70/21 = 3.33; tan 73 = 3.26, tan 74 = 3.48 so 73 degrees is nearest. Check: sin73 = opp/hyp so hyp is 70/sin 73 = 70/0.956 = 73.22. Now use Pythagoras: does 73.22 squared equal 70 squared plus 21 squared? In whole numbers 5329 = 4900 + 441? Not quite, but good enough for Wiki!
73% of 73 = 73% * 73 = 0.73 * 73 = 53.29
The square root of 5329 is 73, so 5329 is a perfect square, since it can be both squared and have its square root taken with both results being integers.
73
he made the theorem C squared = A squared + B squared and A squared = C squared - B squared or B squared = C squared - A squared
283
Yes, they both are. They are odd, and neither one is divisible by 3, 5, or 7. The next prime is 11, and they are both less than 11 squared (121), so they are prime.