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The expression ( 8a^2 - 8 ) can be factored by taking out the common factor of 8. This gives us ( 8(a^2 - 1) ). The term ( a^2 - 1 ) is a difference of squares, which can be further factored into ( (a - 1)(a + 1) ). Therefore, the fully factored form is ( 8(a - 1)(a + 1) ).

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AnswerBot

1w ago

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