Dxdx^(20)
Combine all similar variables in the expression.
Dxdx^(20)=dDx^(21)
To find the derivative of dx^(21)D, multiply the base (D) by the exponent (1), then subtract 1 from the exponent (1-1=0). Since the exponent is now 0, D is eliminated from the term.
Dxdx^(20)=dx^(21)
The derivative of Dxdx^(20) is dx^(21).
dx^(21)
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The answer is: L = pi x (D + d)/2 + 2 x ( C x Cos(a) + a x (D-d)/2) where a = arcsin(D-d)/(2 x C) in radians. Where C is the center distance, D is the large pulley diameter, and d is the small pulley diameter.
d=3c
500 + 300 + 20 + 9 = d c c c x x i x
Show that sec'x = d/dx (sec x) = sec x tan x. First, take note that sec x = 1/cos x; d sin x = cos x dx; d cos x = -sin x dx; and d log u = du/u. From the last, we have du = u d log u. Then, letting u = sec x, we have, d sec x = sec x d log sec x; and d log sec x = d log ( 1 / cos x ) = -d log cos x = d ( -cos x ) / cos x = sin x dx / cos x = tan x dx. Thence, d sec x = sec x tan x dx, and sec' x = sec x tan x, which is what we set out to show.
d/dx(x + 2) = d/dx(x) + d/dx(2) = 1 + 0 = 1