12
p4 - 7p2 + p + 1 = p4 - 3p3 + 3p3 - 9p2 + 2p2 - 6p + 7p - 21 + 22 = p3(p -3) + 392(p - 3) + 2p(p - 3) + 7(p - 3) + 22 = (p-3)(p3 + 39p2 + 2p + 7) + 22 So (p4 - 7p2 + p + 1) / (p-3) = (p3 + 39p2 + 2p + 7) + 22/(p - 3)
p+3 ----- = 4... Therefore p=37 OR 10 p+3/10 = 4... therefore p=3.7
3 + 19 = p22 = p
1/3 of 27 p = 27 p/3 = 9 p
p-3=8 add 3 both sides p-3+3=8+3 solve p=11
The expression is: p/3
p^3 ÷ p^2 = p^(3-2) = p^1 = p
3 times (p * p * p) 3p3 3 = coefficient p = base 3 = exponent
3 + P = 8 Therefore: P = 8 - 3 P = 5
Ah, what a happy little math problem we have here! When you see "p times p to the third power," you simply need to multiply p by p cubed. This gives you p to the power of 4, as you add the exponents when you multiply like bases. Just a joyful reminder to embrace mistakes as happy little accidents in your math journey!
p2 + 9p + 18/ p + 6(p + 6)(p + 3)/ p + 6(p + 6)(p + 3)/ p + 6p + 3
12
To solve for p, set up the equation 5p + 9 = p - 3 5p = p - 12 4p = -12 p = -3 to prove the answer, substitute -3 for p and prove 5(-3) + 9 = (-3) -3 -15 + 9 = -6 -6 = -6
p4 - 7p2 + p + 1 = p4 - 3p3 + 3p3 - 9p2 + 2p2 - 6p + 7p - 21 + 22 = p3(p -3) + 392(p - 3) + 2p(p - 3) + 7(p - 3) + 22 = (p-3)(p3 + 39p2 + 2p + 7) + 22 So (p4 - 7p2 + p + 1) / (p-3) = (p3 + 39p2 + 2p + 7) + 22/(p - 3)
That means the same as p times p times p (that is, "p" appears 3 times as a factor).
p+3 ----- = 4... Therefore p=37 OR 10 p+3/10 = 4... therefore p=3.7