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A bike starts at rest and after 5s it is moving at 5mk what is the average acceleration?
v = u + at where u = starting velocity, v = final velocity, a = acceleration, t = time. Here u = 0 so v = at ie a = v/t Now, v = 5 m/s (what is mk?) and t = 5 s So a = (5 m/s) / 5 s = 1 m/s2
Third equation of motion?
v2- u 2 = 2assince, S (Distance) = Average speed x TimeS = U+V / 2 * TS = U+V / 2 * V - U / A {since T = V -U / A}S = V2 - U2 / 2A2AS = V2 - U2OR V2 - U2 = AsHence, Derived.
What properties must a relation have for it to be called a ''partial ordering''?
For a relation, $, to be called a partial ordering on a set, S, the following three properties must be met:1) If T is any subset of S, then T $ T.2) If T and U are any two subsets of S that meet the condition T $ U as well as the condition U $ T, then T = U.3) If T, U, and V are any three subsets of S that meet the condition T $ U as well as the condition U $ V, then T $ V.For the relation, $, to be called a total ordering on the set, S, the following statement must hold in addition to the previous three:If T and U are any two subsets of S, then either T $ U or U $ T.This final property is called totality.For an example of a partial ordering relation, see the related link on "less than or equal to."Also, see the corresponding related link for the definition of "relation."
How do I rearrange the acceleration formula to solve it for initial velocity?
Where a = (v-u)/t a is acceleration, v is final velocity u is initial velocity t is time so, u=v-at
Equation for acceleration?
acceleration(a) = (final velocity(v) - Initial velocity(u)) / time (s) Algebraically a = (v - u) / t Where 'v' & 'u' are measured in metres per second ( m/s) or ms^-1 And 't' is the time in seconds measured is 's' Hence a(ms^-2) = v(m/s) - u(m/s)) / t(s) And example is a car starting from rest up to 44 m/s ( 30 mph) in 10 seconds. a = (44 - 0 ) / 10 a = 44/10 a = 4.4 ms^-2. NB Earth's gravitational acceleration(g) is approximately 10 ms^-2.
