x(y - 1)(y + 1)
x+y
It is x^2 + xy + y^2
The answer? There is no "answer" There cannot be an answer because they are all different. In order to make calculations, the variables have to be the same. x squared, xy, y squared are the variables, and none of them match. Therefore your "answer" must look like this: 9x squared - 6xy + y squared - 81. Hope I Helped :D
Oh, dude, x times xy is just x squared y. It's like multiplying x by itself and then throwing in a y for good measure. So, if x was 2 and y was 3, you'd get 2 squared times 3, which is 4 times 3, which is 12. Math can be fun, right?
The GCF is xy
The only common factor to all terms is yz. → xy³z² + y²z + xyz = yz(xy²z + y + x)
x(y - 1)(y + 1)
4
x+y
x=y+3t Original formula: y2 -xy = 9t2 -3xt (assumes you meant "9 times t2 " and not (9t)2 ) y2 = xy +9t2 -3xt y2 - 9t2 = xy - 3xt (y-3t)(y+3t) = x(y-3t) (y-3t) = x
y/y2 = 1/y
Divide by 'x'; x2+xy/x = x(x+y)
It is x^2 + xy + y^2
x2y + axy + abx + a2b Factor by grouping. xy(x + a) + ab(x + a) (xy + ab)(x + a)
(x2 - y2)/(x - y) = (x + y)(x - y)/(x - y) = x + y
y=f(x)= x(2x+y)=7 f(x)=2x^2 +xy -7 = 0 y=2x^2 +xy -7 y-xy -7 + 2x^2 = 0 y(1-x)=2x^2-7 y=(2x^2-7) / (1-x) Excuse the working. Y equals 2 X squared minus 7 all divided by 1-X