y plus 3 1 2x plus 1 can be graphed by first finding the values of Y and X coordinates.
2x + 3y = 1 y = 1/3 - 2x/3
Both equations are equal and so: 3x+1 = 2x+3 3x-2x = 3-1 x = 2 and by substituting y = 7
If: x+y = 4 and y = 2x+1 Then: 4-x = 2x+1 => 3 = 3x => 1 = x So by substitution: x = 1 and y = 3
x = 3 y = 4 2x + y - 1 = (6) + (4) - 1 = 9
y plus 3 1 2x plus 1 can be graphed by first finding the values of Y and X coordinates.
4
2x + 3y = 1 y = 1/3 - 2x/3
Both equations are equal and so: 3x+1 = 2x+3 3x-2x = 3-1 x = 2 and by substituting y = 7
x= (-1/2)y-2.5
If: x+y = 4 and y = 2x+1 Then: 4-x = 2x+1 => 3 = 3x => 1 = x So by substitution: x = 1 and y = 3
No but y = -1/2x+3 is perpendicular to y = 2x+6
x = 3 y = 4 2x + y - 1 = (6) + (4) - 1 = 9
Y = 2x + 1
(2, 1)
(3, 1)
5x+2x-3y+y = (5+2)x+(-3+1)y = 7x - 2y