A four log kill is where a disinfectant (or process) is able to kill 10e4 (10,000) organisms of a test inoculum. A four log kill can also be expressed as killing 99.99% of organisms. In many cases, a four log kill is considered the minimum level of high level disinfection, with a six log kill being required for higher threat agents such as anthrax, etc.
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log(2) + log(4) = log(2x)log(2 times 4) = log(2x)2 times 4 = 2 times 'x'x = 4
log x = -4 => x = 10-4 = 0.0001
log3 + logx=4 log(3x)=4 3x=10^4 x=10,000/3
log(x) + 4 - log(6) = 1 so log(x) + 4 + log(1/6) = 1 Take exponents to the base 10 and remember that 10log(x) = x: x * 104 * 1/6 = 10 x = 6/1000 or 0.006
can't really work out what you're asking here but log(a) - log(b) = Log (a/b) and n·log(b) = log(bⁿ)