A four log kill is where a disinfectant (or process) is able to kill 10e4 (10,000) organisms of a test inoculum. A four log kill can also be expressed as killing 99.99% of organisms. In many cases, a four log kill is considered the minimum level of high level disinfection, with a six log kill being required for higher threat agents such as anthrax, etc.
log(2) + log(4) = log(2x)log(2 times 4) = log(2x)2 times 4 = 2 times 'x'x = 4
log x = -4 => x = 10-4 = 0.0001
log3 + logx=4 log(3x)=4 3x=10^4 x=10,000/3
log(x) + 4 - log(6) = 1 so log(x) + 4 + log(1/6) = 1 Take exponents to the base 10 and remember that 10log(x) = x: x * 104 * 1/6 = 10 x = 6/1000 or 0.006
can't really work out what you're asking here but log(a) - log(b) = Log (a/b) and n·log(b) = log(bⁿ)
log(2) + log(4) = log(2x)log(2 times 4) = log(2x)2 times 4 = 2 times 'x'x = 4
k=log4 91.8 4^k=91.8 -- b/c of log rules-- log 4^k=log 91.8 -- b/c of log rules-- k*log 4=log91.8 --> divide by log 4 k=log 91.8/log 4 k= 3.260
by iron or log
log 0.0001= -4
reboot
to log to the dragon and kill it
No. log 20 is a positive number , so it you subtract it from log 5 you get less than log 5. However, log10 5 = 1 - log102 = 2- log1020 . or log 5 - log 20 = log 5 - log 4*5 = log 5 - (log 5 + log 4) = log 5 - log 5 - log 4 = - log 4 But we do not need to do all of these computations, because log 5 is different from log 5 - log 20 by the law of the equality that says two equals remain equal if and only if we subtract (in our case) the same thing from them.
-2
The 'common' log of 4 is 0.60206 (rounded) The 'natural' log of 4 is 1.3863 (rounded)
log x = -4 => x = 10-4 = 0.0001
4 divided by 84 in log div = 0.047619047619047616
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