A four log kill is where a disinfectant (or process) is able to kill 10e4 (10,000) organisms of a test inoculum. A four log kill can also be expressed as killing 99.99% of organisms. In many cases, a four log kill is considered the minimum level of high level disinfection, with a six log kill being required for higher threat agents such as anthrax, etc.
log(2) + log(4) = log(2x)log(2 times 4) = log(2x)2 times 4 = 2 times 'x'x = 4
log x = -4 => x = 10-4 = 0.0001
log3 + logx=4 log(3x)=4 3x=10^4 x=10,000/3
log(x) + 4 - log(6) = 1 so log(x) + 4 + log(1/6) = 1 Take exponents to the base 10 and remember that 10log(x) = x: x * 104 * 1/6 = 10 x = 6/1000 or 0.006
6
log(2) + log(4) = log(2x)log(2 times 4) = log(2x)2 times 4 = 2 times 'x'x = 4
k=log4 91.8 4^k=91.8 -- b/c of log rules-- log 4^k=log 91.8 -- b/c of log rules-- k*log 4=log91.8 --> divide by log 4 k=log 91.8/log 4 k= 3.260
by iron or log
log 0.0001= -4
No. log 20 is a positive number , so it you subtract it from log 5 you get less than log 5. However, log10 5 = 1 - log102 = 2- log1020 . or log 5 - log 20 = log 5 - log 4*5 = log 5 - (log 5 + log 4) = log 5 - log 5 - log 4 = - log 4 But we do not need to do all of these computations, because log 5 is different from log 5 - log 20 by the law of the equality that says two equals remain equal if and only if we subtract (in our case) the same thing from them.
reboot
to log to the dragon and kill it
-2
The 'common' log of 4 is 0.60206 (rounded) The 'natural' log of 4 is 1.3863 (rounded)
log x = -4 => x = 10-4 = 0.0001
4 divided by 84 in log div = 0.047619047619047616
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