The simplified answer is: 4c+2b
c-2b
To solve for ( x ) in the equation ( 4bx - 5 = 5c ), first add 5 to both sides to get ( 4bx = 5c + 5 ). Then, divide both sides by ( 4b ) to isolate ( x ): [ x = \frac{5c + 5}{4b}. ] Thus, the value of ( x ) is ( \frac{5(c + 1)}{4b} ).
They are terms of an algebraic expression that can be simplified to: 2b+2c
2s-2b= a+b+c-2b simplified that would be a+c-b.
If 2b a plus c, then we can say that 3tan A 2tan c = 21.
The like terms are sums of b terms and c terms separately 5c+2c+3c+4b 5c +2c + 4b + 3c => 10c + 4b
c-2b
4b
4b - 2c is an expression, which is equal to 2(2b - c)
2a + 4b + 8c = 2(a + 2b + 4c) You could also continue by factoring the inside of the parentheses a bit: 2a + 4b + 8c = 2(a + 2b + 4c) = 2(a + 2[b + 2c])
a + 2b = c a = c - 2b
They are terms of an algebraic expression that can be simplified to: 2b+2c
If: a = 2b+c Then: a-c = 2b And: b = (a-c)/2
a = 2b + c then a - 2b = c ie c = a - 2b
2s-2b= a+b+c-2b simplified that would be a+c-b.
I think it would be possible to get a 4A,5C or a 4B (C)
If 2b a plus c, then we can say that 3tan A 2tan c = 21.