All multiples of 47, which is an infinite number.
47 is a prime number and is divisible by 1 and 47 only. 51 is divisible by 1, 3, 17, 51.
no
No. it is not
No.
As 235 is ending by a 5 then it is divisible by 5 As 235 is not even it is not divisible by 2 As 2+3+5 is not divisible by 3, 235 is not divisible by 3 235/5 = 47 47 is prime so 235 = 5 * 47 and there's no other way to factorize it
No. 47 is a prime number and is only divisible by 1 and itself.
47 is a prime number and is divisible by 1 and 47 only. 51 is divisible by 1, 3, 17, 51.
No.
no
No. it is not
No. 47 is not evenly divisible by 11.
As 235 is ending by a 5 then it is divisible by 5 As 235 is not even it is not divisible by 2 As 2+3+5 is not divisible by 3, 235 is not divisible by 3 235/5 = 47 47 is prime so 235 = 5 * 47 and there's no other way to factorize it
A number is divisible by 10 if its last digit is 0. To determine if a number is divisible by 235, it must be divisible by both 5 and 47 (since 235 = 5 × 47). Therefore, for a number to be divisible by both 235 and 10, it must end in 0 (for divisibility by 10) and be divisible by 47.
1 47 is only evenly divisible by 1.
yes
yes
no