To find the image of the point (3, 5) after a rotation of -90º (which is equivalent to a clockwise rotation of 90º), you can use the rotation formula. The new coordinates will be (y, -x), which transforms the point (3, 5) into (5, -3). So, the image of the point (3, 5) after a -90º rotation is (5, -3).
To find the image of the point (3, 5) reflected across the x-axis, you keep the x-coordinate the same and negate the y-coordinate. Thus, the reflection of (3, 5) across the x-axis is (3, -5).
3 and 90
2 x 3 x 3 x 5 = 90
3 x 90 equals 270.
Since 3 is a factor of 90, it is automatically the GCF.
To find the image of the point (4, 3) after a -90-degree rotation (which is equivalent to a 90-degree clockwise rotation), you can use the rotation formula: (x', y') = (y, -x). Applying this to the point (4, 3), the new coordinates become (3, -4). Therefore, the image of the point (4, 3) after a -90-degree rotation is (3, -4).
The image is (-5, 3)
To find the image of the point (4, 3) after a 90-degree rotation counterclockwise about the origin, you can use the transformation formula for rotation. The new coordinates will be (-y, x), which means the image of the point (4, 3) will be (-3, 4).
The answer depends on the centre of rotation. A rotation cannot be described without specifying the centre of rotation.
The answer depends on the centre of rotation. A rotation cannot be described without specifying the centre of rotation.
The answer depends on the centre of rotation. A rotation cannot be described without specifying the centre of rotation.
What is the image of point (3, 5) if the rotation is
It is: (-4, -3)
It is: (-4, -3)
It then is: (-3, -5)
Conventionally positive angles are measured anticlockwise. It depends where the centre of rotation is, so where would you like the image to be? If the centre is at, say, (3, 5) then the image will be at (3, 5) regardless of the angle of rotation. If the centre is at, say, (3, 3) then the image will be at (5, 3) If the centre is at, say, the origin, ie (0, 0) then the image will be at (5, -3).
The answer will depend on where the centre of rotation is. Since that it not specified, the image could by anywhere.