Q: What is m in slope equation of a line?

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Given a point P = (a,b) and slope m, the equation of a line through P with slope m is (y-b) = m(x-a)

The straight line equation would depend on the slope which has not been given.

16

y = mx + c is the equation of a straight oblique line where m = gradient The gradient is a measue of the steepness of a line (or a measure of the slope of the line)

In the straight line equation: y = mx+b 'm' is the slope and 'b' is the y intercept

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Given a point P = (a,b) and slope m, the equation of a line through P with slope m is (y-b) = m(x-a)

The straight line equation would depend on the slope which has not been given.

16

There is no equation there but the slope of the line is the number that multiplies x in the straight line equation y = mx + b whereas m is the slope and b is the y intercept

y = mx + c is the equation of a straight oblique line where m = gradient The gradient is a measue of the steepness of a line (or a measure of the slope of the line)

If the slope is m, then the equation is y - 7 = m*(x + 3)

If the slope m is given at a point (xo, yo) of a line, then the equation of the line is given by: y - yo = m(x - xo)

In the straight line equation: y = mx+b 'm' is the slope and 'b' is the y intercept

The equation of a line is y=mx+b, when m is the slope of the line and b is the y-intercept.

Assuming that you meant that the equation is y=3x+1, the slope is 3. This is because the equation of any line in the form of y=mx+b has a slope of "m". Therefore, the value of m in this equation is 3.

Another point is needed to work out the slope and its straight line equation. Slope is worked out as: (y2-y1)/(x2-x1) ----------------------- With slope m and going through a point (x0, y0), a line has equation: y - y0 = m(x - x0) Thus the point-slope equation of a line with slope m through the point (-1, 2) is given by: y - 2 = m(x - -1) → y - 2 = m(x + 1)

If you mean: y = mx+b then the slope of the line is m and the y intercept is b