It is the slope.
Given a point P = (a,b) and slope m, the equation of a line through P with slope m is (y-b) = m(x-a)
To write the point-slope equation of a line that passes through the point (5, 5), you need a slope (m) as well. The point-slope form is given by the equation ( y - y_1 = m(x - x_1) ). If the slope is not provided, you can express the equation generically as ( y - 5 = m(x - 5) ), where ( m ) is the slope of the line. If you have a specific slope, you can substitute it into the equation.
The straight line equation would depend on the slope which has not been given.
16
The equation of a line in slope-intercept form is given by ( y = mx + b ), where ( m ) is the slope and ( b ) is the y-intercept. For a line with a slope ( m = 3 ) and a y-intercept ( b = 8.25 ), the equation is: [ y = 3x + 8.25. ]
Given a point P = (a,b) and slope m, the equation of a line through P with slope m is (y-b) = m(x-a)
To write the point-slope equation of a line that passes through the point (5, 5), you need a slope (m) as well. The point-slope form is given by the equation ( y - y_1 = m(x - x_1) ). If the slope is not provided, you can express the equation generically as ( y - 5 = m(x - 5) ), where ( m ) is the slope of the line. If you have a specific slope, you can substitute it into the equation.
The straight line equation would depend on the slope which has not been given.
16
There is no equation there but the slope of the line is the number that multiplies x in the straight line equation y = mx + b whereas m is the slope and b is the y intercept
The equation of a line in slope-intercept form is given by ( y = mx + b ), where ( m ) is the slope and ( b ) is the y-intercept. For a line with a slope ( m = 3 ) and a y-intercept ( b = 8.25 ), the equation is: [ y = 3x + 8.25. ]
y = mx + c is the equation of a straight oblique line where m = gradient The gradient is a measue of the steepness of a line (or a measure of the slope of the line)
To find the slope of the line given by the equation ( y = 12x - 23 ), we can identify the slope from the standard slope-intercept form ( y = mx + b ), where ( m ) is the slope and ( b ) is the y-intercept. In this equation, the slope ( m ) is 12. Therefore, the slope of the line is 12.
The point-slope form of a line's equation is given by (y - y_1 = m(x - x_1)), where (m) is the slope and ((x_1, y_1)) is a point on the line. Given the slope (m = -5) and the point ((1, -1)), the equation in point-slope form is (y + 1 = -5(x - 1)).
To find the equation of a line that is perpendicular to another line, you first need the slope of the original line. If the slope of the original line is ( m ), then the slope of the perpendicular line will be ( -\frac{1}{m} ). Assuming you know the slope ( m ), you can then use the point-slope form of a line, ( y - y_1 = m(x - x_1) ). For the point (6, 8), the equation becomes ( y - 8 = -\frac{1}{m}(x - 6) ) if you replace ( m ) with the negative reciprocal of the original slope.
The point-slope equation of a line is given by the formula ( y - y_1 = m(x - x_1) ), where ( m ) is the slope and ( (x_1, y_1) ) is a point on the line. If the slope is not specified, let's denote it as ( m ). For the point (-1, -3), the equation becomes ( y + 3 = m(x + 1) ). This can be rearranged to express the line in point-slope form.
If the slope is m, then the equation is y - 7 = m*(x + 3)