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What is point slope form of an equation of a line?
Given a point P = (a,b) and slope m, the equation of a line through P with slope m is (y-b) = m(x-a)
What is the point slope equation for the line that passes through the point 5 and 5?
To write the point-slope equation of a line that passes through the point (5, 5), you need a slope (m) as well. The point-slope form is given by the equation ( y - y_1 = m(x - x_1) ). If the slope is not provided, you can express the equation generically as ( y - 5 = m(x - 5) ), where ( m ) is the slope of the line. If you have a specific slope, you can substitute it into the equation.
What is the equation of a line passing through (-6 5) and having a slope of?
The straight line equation would depend on the slope which has not been given.
What is the slope of the line with equation Y equals 4X-12?
16
What is the equation of the line with m 3 and b 8.25?
The equation of a line in slope-intercept form is given by ( y = mx + b ), where ( m ) is the slope and ( b ) is the y-intercept. For a line with a slope ( m = 3 ) and a y-intercept ( b = 8.25 ), the equation is: [ y = 3x + 8.25. ]
What is point slope form of an equation of a line?
Given a point P = (a,b) and slope m, the equation of a line through P with slope m is (y-b) = m(x-a)
What is the point slope equation for the line that passes through the point 5 and 5?
To write the point-slope equation of a line that passes through the point (5, 5), you need a slope (m) as well. The point-slope form is given by the equation ( y - y_1 = m(x - x_1) ). If the slope is not provided, you can express the equation generically as ( y - 5 = m(x - 5) ), where ( m ) is the slope of the line. If you have a specific slope, you can substitute it into the equation.
What is the equation of a line passing through (-6 5) and having a slope of?
The straight line equation would depend on the slope which has not been given.
What is the slope of the line with equation Y equals 4X-12?
16
What is the equation of the line with m 3 and b 8.25?
The equation of a line in slope-intercept form is given by ( y = mx + b ), where ( m ) is the slope and ( b ) is the y-intercept. For a line with a slope ( m = 3 ) and a y-intercept ( b = 8.25 ), the equation is: [ y = 3x + 8.25. ]
What is the slope of the line given by the equation below?
There is no equation there but the slope of the line is the number that multiplies x in the straight line equation y = mx + b whereas m is the slope and b is the y intercept
The slope-intercept equation of a line is y equals mx plus b where m is the slope of the line?
y = mx + c is the equation of a straight oblique line where m = gradient The gradient is a measue of the steepness of a line (or a measure of the slope of the line)
What is the slope of the line given by the equation below y 12x - 23?
To find the slope of the line given by the equation ( y = 12x - 23 ), we can identify the slope from the standard slope-intercept form ( y = mx + b ), where ( m ) is the slope and ( b ) is the y-intercept. In this equation, the slope ( m ) is 12. Therefore, the slope of the line is 12.
Who A line has a slope of -5 and passes through 1 -1 Which is the equation of the line in point-slope form?
The point-slope form of a line's equation is given by (y - y_1 = m(x - x_1)), where (m) is the slope and ((x_1, y_1)) is a point on the line. Given the slope (m = -5) and the point ((1, -1)), the equation in point-slope form is (y + 1 = -5(x - 1)).
What is the equation of a line that is perpendicular to and passes through the point (6 8)?
To find the equation of a line that is perpendicular to another line, you first need the slope of the original line. If the slope of the original line is ( m ), then the slope of the perpendicular line will be ( -\frac{1}{m} ). Assuming you know the slope ( m ), you can then use the point-slope form of a line, ( y - y_1 = m(x - x_1) ). For the point (6, 8), the equation becomes ( y - 8 = -\frac{1}{m}(x - 6) ) if you replace ( m ) with the negative reciprocal of the original slope.
What is the point-slope equation of the line with slope that goes through the point -1 -3?
The point-slope equation of a line is given by the formula ( y - y_1 = m(x - x_1) ), where ( m ) is the slope and ( (x_1, y_1) ) is a point on the line. If the slope is not specified, let's denote it as ( m ). For the point (-1, -3), the equation becomes ( y + 3 = m(x + 1) ). This can be rearranged to express the line in point-slope form.
What is the equation of a line passing through -3 7 and having a slope of?
If the slope is m, then the equation is y - 7 = m*(x + 3)
