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How do you solve a to the power of m times a to the power of n?
You don't solve it!!! It is a method of manipulation of indices. a^(n) X a^(m) = a^(n+m) Similarly, a^(n) / a^(m) = a^(n-m) [a^(n)]^(m) = a^(nm)
What is the five law of exponents?
The five laws of exponents are: Product of Powers: ( a^m \times a^n = a^{m+n} ) — When multiplying like bases, add the exponents. Quotient of Powers: ( \frac{a^m}{a^n} = a^{m-n} ) — When dividing like bases, subtract the exponents. Power of a Power: ( (a^m)^n = a^{m \times n} ) — When raising a power to another power, multiply the exponents. Power of a Product: ( (ab)^n = a^n \times b^n ) — Distribute the exponent to each factor inside the parentheses. Power of a Quotient: ( \left(\frac{a}{b}\right)^n = \frac{a^n}{b^n} ) — Distribute the exponent to the numerator and denominator.
What are the different laws of integer exponents?
The laws of integer exponents include the following key rules: Product of Powers: ( a^m \cdot a^n = a^{m+n} ) Quotient of Powers: ( \frac{a^m}{a^n} = a^{m-n} ) (for ( a \neq 0 )) Power of a Power: ( (a^m)^n = a^{m \cdot n} ) Power of a Product: ( (ab)^n = a^n \cdot b^n ) Power of a Quotient: ( \left(\frac{a}{b}\right)^n = \frac{a^n}{b^n} ) (for ( b \neq 0 )) These laws help simplify expressions involving exponents and are fundamental in algebra.
Program to find n raise to the power m?
P = 1 For K = 1 to M . P = P * N Next K PRINT "N raised to the power of M is "; P
What is the answer to -2m to the fourth power times n to the 6thpower to the 2nd power?
The question is open to multiple interpretations but I think you mean [(-2m)^4] x (n^6)^2 = [(-2)^4](m^4)(n^12) = 16(m^4)(n^12) or 16 times m to the 4th power times n to the 12th power.
How do you solve a to the power of m times a to the power of n?
You don't solve it!!! It is a method of manipulation of indices. a^(n) X a^(m) = a^(n+m) Similarly, a^(n) / a^(m) = a^(n-m) [a^(n)]^(m) = a^(nm)
How do you solve M to the power of 4 times N to the power of 5 minus M to the power of 20 times N to the power of 21 m4 n5 - m20n21?
m^4 n^5 - m^20 n^21
What are m and n when 4 over n times 9 times 2 over 9 whole thing powered n minus 2 times x power 6 minus 2n equals m over x power 2?
[(4/n)(9)(2/9)]^n -2x^6 - 2n=m/x^2 (8/n)^2 - 2x^6 -2n=m/x^2 (64x^2)/n^2 -2x^8 -2nx^2=m Now we know what m equals. I've got to go now. Sorry!
X over m minus y over n equals to 1 what is m?
m = xn/(n + y)
Program to find n raise to the power m?
P = 1 For K = 1 to M . P = P * N Next K PRINT "N raised to the power of M is "; P
How much pressure is exerted by applying 1000 n of force over 2 m power to 2 of area?
The pressure exerted is 500 Pa. This is calculated by dividing the force (1000 N) by the area (2 m²) over which the force is applied.
What is the answer to -2m to the fourth power times n to the 6thpower to the 2nd power?
The question is open to multiple interpretations but I think you mean [(-2m)^4] x (n^6)^2 = [(-2)^4](m^4)(n^12) = 16(m^4)(n^12) or 16 times m to the 4th power times n to the 12th power.
What is M to the fourth power Times n to the fourth power?
m4n4
The power required to exert 1 N force over a distance of 1 m in 1 second is?
The power required to exert a force of 1 N over a distance of 1 m in 1 second is 1 watt. This is because power is defined as the rate at which work is done, and in this case, the work done is 1 joule in 1 second.
How do you make x the subject of m equals n plus (x over p)?
If: m = n+x/p then x = p(m-n)
What are some seven letter words with 1st letter M and 5th letter N and 7th letter N?
According to SOWPODS (the combination of Scrabble dictionaries used around the world) there are 2 words with the pattern M---N-N. That is, seven letter words with 1st letter M and 5th letter N and 7th letter N. In alphabetical order, they are: meconin melanin
X to the third power times x to the fourth power?
X to the 7th power. X^m*X^n=X^m+n That means when you multiply variables with the same base, you add the exponents.
