You don't solve it!!! It is a method of manipulation of indices. a^(n) X a^(m) = a^(n+m) Similarly, a^(n) / a^(m) = a^(n-m) [a^(n)]^(m) = a^(nm)
The five laws of exponents are: Product of Powers: ( a^m \times a^n = a^{m+n} ) — When multiplying like bases, add the exponents. Quotient of Powers: ( \frac{a^m}{a^n} = a^{m-n} ) — When dividing like bases, subtract the exponents. Power of a Power: ( (a^m)^n = a^{m \times n} ) — When raising a power to another power, multiply the exponents. Power of a Product: ( (ab)^n = a^n \times b^n ) — Distribute the exponent to each factor inside the parentheses. Power of a Quotient: ( \left(\frac{a}{b}\right)^n = \frac{a^n}{b^n} ) — Distribute the exponent to the numerator and denominator.
The laws of integer exponents include the following key rules: Product of Powers: ( a^m \cdot a^n = a^{m+n} ) Quotient of Powers: ( \frac{a^m}{a^n} = a^{m-n} ) (for ( a \neq 0 )) Power of a Power: ( (a^m)^n = a^{m \cdot n} ) Power of a Product: ( (ab)^n = a^n \cdot b^n ) Power of a Quotient: ( \left(\frac{a}{b}\right)^n = \frac{a^n}{b^n} ) (for ( b \neq 0 )) These laws help simplify expressions involving exponents and are fundamental in algebra.
P = 1 For K = 1 to M . P = P * N Next K PRINT "N raised to the power of M is "; P
To raise an exponent, you multiply the existing exponent by the new exponent. For example, if you have ( a^m ) and want to raise it to the power of ( n ), you would calculate ( (a^m)^n = a^{m \cdot n} ). This follows the power of a power rule in exponentiation.
You don't solve it!!! It is a method of manipulation of indices. a^(n) X a^(m) = a^(n+m) Similarly, a^(n) / a^(m) = a^(n-m) [a^(n)]^(m) = a^(nm)
m^4 n^5 - m^20 n^21
[(4/n)(9)(2/9)]^n -2x^6 - 2n=m/x^2 (8/n)^2 - 2x^6 -2n=m/x^2 (64x^2)/n^2 -2x^8 -2nx^2=m Now we know what m equals. I've got to go now. Sorry!
m = xn/(n + y)
The five laws of exponents are: Product of Powers: ( a^m \times a^n = a^{m+n} ) — When multiplying like bases, add the exponents. Quotient of Powers: ( \frac{a^m}{a^n} = a^{m-n} ) — When dividing like bases, subtract the exponents. Power of a Power: ( (a^m)^n = a^{m \times n} ) — When raising a power to another power, multiply the exponents. Power of a Product: ( (ab)^n = a^n \times b^n ) — Distribute the exponent to each factor inside the parentheses. Power of a Quotient: ( \left(\frac{a}{b}\right)^n = \frac{a^n}{b^n} ) — Distribute the exponent to the numerator and denominator.
The laws of integer exponents include the following key rules: Product of Powers: ( a^m \cdot a^n = a^{m+n} ) Quotient of Powers: ( \frac{a^m}{a^n} = a^{m-n} ) (for ( a \neq 0 )) Power of a Power: ( (a^m)^n = a^{m \cdot n} ) Power of a Product: ( (ab)^n = a^n \cdot b^n ) Power of a Quotient: ( \left(\frac{a}{b}\right)^n = \frac{a^n}{b^n} ) (for ( b \neq 0 )) These laws help simplify expressions involving exponents and are fundamental in algebra.
P = 1 For K = 1 to M . P = P * N Next K PRINT "N raised to the power of M is "; P
To raise an exponent, you multiply the existing exponent by the new exponent. For example, if you have ( a^m ) and want to raise it to the power of ( n ), you would calculate ( (a^m)^n = a^{m \cdot n} ). This follows the power of a power rule in exponentiation.
The pressure exerted is 500 Pa. This is calculated by dividing the force (1000 N) by the area (2 m²) over which the force is applied.
When multiplying exponents with the same base, you add the exponents (a^m × a^n = a^(m+n)). Conversely, when dividing exponents with the same base, you subtract the exponents (a^m ÷ a^n = a^(m-n)). If raising a power to another power, you multiply the exponents ( (a^m)^n = a^(m*n) ). Finally, for any non-zero base raised to the power of zero, the result is always one (a^0 = 1).
The question is open to multiple interpretations but I think you mean [(-2m)^4] x (n^6)^2 = [(-2)^4](m^4)(n^12) = 16(m^4)(n^12) or 16 times m to the 4th power times n to the 12th power.
To calculate ( n^3 ) raised to the 43rd power, you can use the exponentiation rule which states that ( (a^m)^n = a^{m \cdot n} ). Therefore, ( (n^3)^{43} = n^{3 \cdot 43} = n^{129} ). Thus, ( n^3 ) to the 43rd power is ( n^{129} ).