6
4 + 3c = 2c + 2Subtract 4 from each side:3c = 2c - 2Subtract 2c from each side:c = -2
If you meant you want to solve for c on: 5c-3 = 2c+6 you have to simplify the formula. Step 1: Subtract 2c from both sides: 3c-3 = 6 Step 2: Add 3 to both sides 3c = 9 Step 3: Divide both sides by 3 c = 3
3c - 12 = 14 + 5cSubtract 3c from each side:-12 = 14 + 2cSubtract 14 from each side:-26 = 2cDivide each side by 2:-13 = c
1
meaning of design concept in architecture
3c+6=18 3c+6-6=18-6 3c=12 3c÷3=12÷3 c=4
3c-7 = -4
2y-3c = -1
The solution (not sum) to the equation 21 = 3c + 6 is as follows:21 = 3c + 621 - 6 = 3c + 6 - 615 = 3c3c = 153c/3 = 21/3c = 7
42 is a multiple of 3. 42c is a multiple of 3c. 42 can be but is not necessarily a multiple of 3c.
3c x 8e = 24
(8 - 3c)(8 + 3c)
3c-d
It is: -28+21c = -7(4-3c)
2c-10
The GCF is 3c^5