No. Say your matrix is called A, then a number e is an eigenvalue of A exactly when A-eI is singular, where I is the identity matrix of the same dimensions as A. A-eI is singular exactly when (A-eI)T is singular, but (A-eI)T=AT-(eI)T =AT-eI. Therefore we can conclude that e is an eigenvalue of A exactly when it is an eigenvalue of AT.
how does ahp use eigen values and eigen vectors
There is no such word as a "hapliod". If you meant haploid, the answer depends on the species.There is no such word as a "hapliod". If you meant haploid, the answer depends on the species.There is no such word as a "hapliod". If you meant haploid, the answer depends on the species.There is no such word as a "hapliod". If you meant haploid, the answer depends on the species.
If a linear transformation acts on a vector and the result is only a change in the vector's magnitude, not direction, that vector is called an eigenvector of that particular linear transformation, and the magnitude that the vector is changed by is called an eigenvalue of that eigenvector.Formulaically, this statement is expressed as Av=kv, where A is the linear transformation, vis the eigenvector, and k is the eigenvalue. Keep in mind that A is usually a matrix and k is a scalar multiple that must exist in the field of which is over the vector space in question.
The word "meant" has one syllable.
No.
Yes, it is.
define eigen value problem
No. Say your matrix is called A, then a number e is an eigenvalue of A exactly when A-eI is singular, where I is the identity matrix of the same dimensions as A. A-eI is singular exactly when (A-eI)T is singular, but (A-eI)T=AT-(eI)T =AT-eI. Therefore we can conclude that e is an eigenvalue of A exactly when it is an eigenvalue of AT.
how does ahp use eigen values and eigen vectors
There is no such word as a "hapliod". If you meant haploid, the answer depends on the species.There is no such word as a "hapliod". If you meant haploid, the answer depends on the species.There is no such word as a "hapliod". If you meant haploid, the answer depends on the species.There is no such word as a "hapliod". If you meant haploid, the answer depends on the species.
If a linear transformation acts on a vector and the result is only a change in the vector's magnitude, not direction, that vector is called an eigenvector of that particular linear transformation, and the magnitude that the vector is changed by is called an eigenvalue of that eigenvector.Formulaically, this statement is expressed as Av=kv, where A is the linear transformation, vis the eigenvector, and k is the eigenvalue. Keep in mind that A is usually a matrix and k is a scalar multiple that must exist in the field of which is over the vector space in question.
Yes it is. In fact, every singular operator (read singular matrix) has 0 as an eigenvalue (the converse is also true). To see this, just note that, by definition, for any singular operator A, there exists a nonzero vector x such that Ax = 0. Since 0 = 0x we have Ax = 0x, i.e. 0 is an eigenvalue of A.
Synonyms of the word meant are; portent, presage, promise, purport, suggest, symbolize. Antonyms of the word meant are; entail, imply, mean, intend, convey.
it meant castle
The word "meant" has one syllable.
"Meant" has one syllable.