Horizontal and Vertical forces respectively.
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In ordered pair forms (0,-5) (1,-4) (2,-3) The first values are the x values and the second values are the y values.
I assume you meant, x + y = 6.Now you can get multiple answers (if x and y are integers).x = 0, y = 6x = 1, y = 5x = 2, y = 4x = 3, y = 3x = 4, y = 2x = 5, y = 1x = 6, y = 0
To find the ordered pairs in any equation, just plug in any number for x and solve for y. If your equation is meant to be y=1+5x, then if x=0 then y=1+5*0, y=1 so the first ordered pair would be (0,1) If your equation is meant to be y=(1/5)x, then if x=0 then y=(1/5)*0, y=0, so the first ordered pair would be (0,0)
If its meant to be: (x-3)^2+(y+1)^2 = 4 then the radius is 2
We let the two numbers be represented by x and y. Then x+y=24 x-y=4 Adding equations yields 2x=28 Or x=14, which forces y=10. 10+14=24, 14-10=4.