Assuming that you meant "x - 4y = 20", the x-intercept is x=20, and the y-intercept is y=-5.
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Substitute the coordinates of the point into the equation of the line. If the equation is still valid then the point is on the line; if not then it is not.
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Well, to answer your question,
The standard equation for a straight line is y = mx + c. Let this be the equation of the original line. Note that m and c are known values. Let the given point coordinates be (a,b)Two straight lines are perpendicular if the product of their gradients (slopes) is -1.The slope (m1) of the perpendicular line is therefore m1 = -1/mWhen y = b then x = a so the equation for the perpendicular line is y = m1x + d, and substituting gives : b = -a/m + d and this will enable d to be calculated.NOTE : In the absence of information for the equation of the original line and the coordinates of the given point then this is a general rather than a specific answer.