Ah, what a happy little math problem we have here! When you see "p times p to the third power," you simply need to multiply p by p cubed. This gives you p to the power of 4, as you add the exponents when you multiply like bases. Just a joyful reminder to embrace mistakes as happy little accidents in your math journey!
3 times (p * p * p) 3p3 3 = coefficient p = base 3 = exponent
That means the same as p times p times p (that is, "p" appears 3 times as a factor).
p 4
When you divide p cubed by p squared, you are essentially dividing p to the power of 3 by p to the power of 2. This simplifies to p^(3-2), which equals p^1. Therefore, the result of p cubed divided by p squared is p.
(p-5•8•4+p)
To cube something is to raise to the third power. P cubed would be p^3
(p-2) x (p5) = p-2+5 = p3
Oh, dude, you're hitting me with some math here! So, "p times p squared" is basically p multiplied by p squared, which is p to the power of 2. When you multiply p by p squared, you're essentially multiplying p by p to the power of 2, which gives you p to the power of 3. So, the answer is p cubed. Math can be fun... sometimes.
3 times (p * p * p) 3p3 3 = coefficient p = base 3 = exponent
If: E*I = P Then: I = P/E
That means the same as p times p times p (that is, "p" appears 3 times as a factor).
one-third of p is at least -17
p 4
5p2 = 315 Therefore, p2 = 315/5 p = sqrt(63) p = ±7.94
When you divide p cubed by p squared, you are essentially dividing p to the power of 3 by p to the power of 2. This simplifies to p^(3-2), which equals p^1. Therefore, the result of p cubed divided by p squared is p.
The commutator of the operator x with the momentum operator p raised to the power of n is ih-bar times n times p(n-1), where h-bar is the reduced Planck constant.
It is P cubed or P3.