answer for (x+5)^2/11^2-(y+16)^2/6^2=1 answer for that Question is (-5,-16)
Please use the Pythagoran property: calculate the square root of ((difference in x-coordinates)2 + (difference in y-coordinates)2).
It is [(3 + -13)/2, (3 + -13)/2] = [-10/2, -10/2] = (-5, -5)
5
Points: (-14, 3) and (2, -5) Slope: -1/2
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answer for (x+5)^2/11^2-(y+16)^2/6^2=1 answer for that Question is (-5,-16)
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Rotating it about the origin 180° (either way, it's half a turn) will transform a point with coordinates (x, y) to that with coordinates (-x, -y) Thus (2, 5) → (-2, -5)
Please use the Pythagoran property: calculate the square root of ((difference in x-coordinates)2 + (difference in y-coordinates)2).
It is [(3 + -13)/2, (3 + -13)/2] = [-10/2, -10/2] = (-5, -5)
trite
5
(2,-5) turns into 2,5
Points: (5, -3) and (8, -5)Slope: -2/3
(-2, -5)
Points: (-14, 3) and (2, -5) Slope: -1/2