answer for (x+5)^2/11^2-(y+16)^2/6^2=1 answer for that Question is (-5,-16)
The point (2, -5) is located in the fourth quadrant of the Cartesian coordinate system. In this quadrant, the x-coordinates are positive, while the y-coordinates are negative. Therefore, since 2 is positive and -5 is negative, the coordinates correspond to the fourth quadrant.
Please use the Pythagoran property: calculate the square root of ((difference in x-coordinates)2 + (difference in y-coordinates)2).
It is [(3 + -13)/2, (3 + -13)/2] = [-10/2, -10/2] = (-5, -5)
5
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answer for (x+5)^2/11^2-(y+16)^2/6^2=1 answer for that Question is (-5,-16)
The point (2, -5) is located in the fourth quadrant of the Cartesian coordinate system. In this quadrant, the x-coordinates are positive, while the y-coordinates are negative. Therefore, since 2 is positive and -5 is negative, the coordinates correspond to the fourth quadrant.
Rotating it about the origin 180° (either way, it's half a turn) will transform a point with coordinates (x, y) to that with coordinates (-x, -y) Thus (2, 5) → (-2, -5)
Please use the Pythagoran property: calculate the square root of ((difference in x-coordinates)2 + (difference in y-coordinates)2).
It is [(3 + -13)/2, (3 + -13)/2] = [-10/2, -10/2] = (-5, -5)
5
(2,-5) turns into 2,5
trite
Points: (5, -3) and (8, -5)Slope: -2/3
(-2, -5)