the relation between frequency and time period is ''t=1/f''
frequency = speed of light/wavelength
the lower the frequency the lower the pitch; higher pitch lower frequency
Speed = (frequency) times (wavelength) Frequency = (speed) divided by (wavelength) Wavelength = (speed) divided by (frequency)
wave length and frequency are the product of the wave speed, so the wave speed is a constant variable and the other two are inversely proportional the wave length increases, as the frequency decreases
No relation is there power factor is a unit less quantity.
the relation between frequency and time period is ''t=1/f''
Frequency = 1 / period
frequency = speed of light/wavelength
usually more power means more range. Now frequency come into play and obstacles to the transmission. there is no definite answer
yes!
voltage and frequency both are different quantity.. don't mix it...
the lower the frequency the lower the pitch; higher pitch lower frequency
In an AC motor, torque is directly proportional to frequency. This means that as the frequency of the power supply increases, the torque produced by the motor also increases. Conversely, decreasing the frequency leads to a decrease in torque.
There is no such equation. The main reason is that there is no relationship between current and frequency.
The relation between cut off frequency (fc) and band width is as follows: fc=Q*B.W where Q=(fL*fH)^1/2/(fH-fL) Q is quality factor. fL is low frequency. fH is high frequency.
Use the relation: speed = frequency x wavelengthUse the relation: speed = frequency x wavelengthUse the relation: speed = frequency x wavelengthUse the relation: speed = frequency x wavelength