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Can someone verify that sec4 theta-sec2 theta equals tan4 theta plus tan2 theta?
sec4(Θ) - sec2(Θ) = tan4(Θ) + tan2(Θ)Factor each side: sec2(Θ) [sec2(Θ) - 1] = tan2(Θ) [tan2(Θ) + 1]Use the identitiy: 1 + tan2(Θ) = sec2(Θ)We can also write it as: tan2(Θ) = sec2(Θ) - 1Substitute the first form of the identity in the right side: sec2(Θ) [sec2(Θ) - 1] = tan2(Θ) sec2(Θ)Substitute the second form of the identity in the left side: sec2(Θ) tan2(Θ) = tan2(Θ) sec2(Θ)Is that close enough for you ?Is it worth a trust point ?
What is the derivitive of tangent?
It is sec2.
How do you convert meter per second squared to km per hour squared?
1 kilometer = 1,000 meters 1 hour = 3,600 seconds 1 meter/sec2 = (1 meter/sec2) x (1 kilometer/1,000 meters) x (3,6002 sec2/hr2) = 12,960 km/hr2 1 km/hr2 = 7.716 x 10-5 meter/sec2
How do you graph a tangent function y equals 2tan 2x?
The derivative of a function is the function's tangent function.So, d(y)/dx = d(2tan(2x))/dx = 2*d(tan(2x))/dx = 2*d(tan(u))/du*du/dx, where u=2x, = 2*sec2(2x)*d(2x)/dx = 4*sec2(2x)*d(x)/dx = 4*sec2(2x)Now just make a plot for y = 4*sec2(2x) and you got your tangent function.
What is the vertical motion model equation?
H= -1/2gt2+vt+s Where H is the ending height g is the rate of gravity (32 ft/sec2 or 9.8 m/sec2) t is the time v is the initial velocity and s is the starting height.
