What is the equation for a line that goes through points -4 16 and 2 -11?

Answer 1

(-4, 16), (2, -11)

First, find the slope of the line.

m = (y2 - y1)/(x2 - x1) = [16 - (-11)]/(-4 - 2) = 27/-6 = -27/6

Use the point-slope form of the equation of the line with m = -27/6, x1 = 2 and y1 = -11.

((y - y1) =m(x - x1) substitute;

y - (-11) = -(27/6)(x - 2)

y + 11 = -(27/6)x + 54/6

y + 11 - 11 = -(27/6)x + 9 - 11

y = -(27/6)x - 3 This is the slope-intercept form of the equation of the line.

The general form of the equation of the line is: Ax + By + C = 0 where A, B, and C are real numbers, and A and B are not both zero.

So, you have:

y = -(27/6)x - 3

y + (27/6)x + 3 = -(27/6)x + (27/6)x - 3 + 3

y + (27/6)x + 3 = 0

(27/6)x + y + 3 = 0