(-4, 16), (2, -11)
First, find the slope of the line.
m = (y2 - y1)/(x2 - x1) = [16 - (-11)]/(-4 - 2) = 27/-6 = -27/6
Use the point-slope form of the equation of the line with m = -27/6, x1 = 2 and y1 = -11.
((y - y1) =m(x - x1) substitute;
y - (-11) = -(27/6)(x - 2)
y + 11 = -(27/6)x + 54/6
y + 11 - 11 = -(27/6)x + 9 - 11
y = -(27/6)x - 3 This is the slope-intercept form of the equation of the line.
The general form of the equation of the line is: Ax + By + C = 0 where A, B, and C are real numbers, and A and B are not both zero.
So, you have:
y = -(27/6)x - 3
y + (27/6)x + 3 = -(27/6)x + (27/6)x - 3 + 3
y + (27/6)x + 3 = 0
(27/6)x + y + 3 = 0
Plug both points into the equation of a line, y =m*x + b and then solve the system of equations for m and b to get equation of the line through the points.
If you mean points of (-4, 2) and (4, -2) Then the straight line equation works out as 2y = -x
If you mean points of: (-1, 5) and (2, -4) Then the equation works out as: y = -3x+2
If the line passes through (5, 2) and (5, 7), then the x value stays constant for those two points, and since it is a line, the x value stays constant for the whole line, so the equation of the line isx = 5
x = 2
Plug both points into the equation of a line, y =m*x + b and then solve the system of equations for m and b to get equation of the line through the points.
Write the equation of the line that passes through the points (3, -5) and (-4, -5)
Points: (5, -2) and (4, 3)Slope: -5Equation: y = -5x+23
The line goes through the midpoint, which is halfway between points. The distances are equal to each other, and proves that they are equidistant.
The formula for a line is: Y = mX + b
In general, a linear equation CANNOT be made to go through three points. That will only happen if the three points are collinear and in that case, the equation of the line will only require two points.
If you mean points of (-4, 2) and (4, -2) Then the straight line equation works out as 2y = -x
The equation is x = 2
If you mean a point of (0, 3) and a slope of 2 then the equation is y = 2x+3
In order to find the equation of a tangent line you must take the derivative of the original equation and then find the points that it passes through.
Points: (0, -2) and (6, 0) Slope: 1/3 Equation of line: 3y = x-6
For any line, there needs to be two points. If the line passes through points and extends in both directions forever, it's a line. If the line just goes between the two points, its called a line segment. If the line goes through both points but only extends in one direction, it's a ray.