The given sequence "0369" appears to represent a repeating pattern of digits. If we assume that the sequence repeats every four digits, the 50th term can be found by calculating the position within the repeating cycle. Dividing 50 by 4 gives a remainder of 2, which corresponds to the second digit in the sequence. Therefore, the 50th term is "3."
To find the 50th term of the sequence formed by the digits 0, 3, 6, and 9, we first observe that the sequence repeats every four terms: 0, 3, 6, 9. To determine the 50th term, we calculate the position in the cycle by finding the remainder of 50 divided by 4, which is 2 (since 50 mod 4 = 2). Therefore, the 50th term corresponds to the second term in the repeating sequence, which is 3.
47
The given sequence is an arithmetic sequence where each term increases by 7. The first term (a) is 3, and the common difference (d) is 7. The formula for the nth term of an arithmetic sequence is given by ( a_n = a + (n - 1) \cdot d ). For the 50th term, ( a_{50} = 3 + (50 - 1) \cdot 7 = 3 + 343 = 346 ).
100
A number is a single term so there cannot be a 50th term for a number.
You need the rule that generates the sequence.
You first have to figure out some rule for the sequence. This can be quite tricky.
47
The given sequence is an arithmetic sequence where each term increases by 7. The first term (a) is 3, and the common difference (d) is 7. The formula for the nth term of an arithmetic sequence is given by ( a_n = a + (n - 1) \cdot d ). For the 50th term, ( a_{50} = 3 + (50 - 1) \cdot 7 = 3 + 343 = 346 ).
50th term of what
100
A number is a single term so there cannot be a 50th term for a number.
By figuring out the rule on which the sequence is based. I am pretty sure the last number is supposed to be 125 - in that case, this is the sequence of cubic numbers: 13, 23, 33, etc.
50th term means n = 50 So the term is 100-50 = 50
2
The nth term in the sequence is defined by t(n) = -1 + 4n where n = 1, 2, 3, ... So t(50) = -1 + 4*50 = -1 + 200 = 199
88