What is the 14th term in the arithmetic sequence in which the first is 100 and the common difference is -4? a14= a + 13d = 100 + 13(-4) = 48
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The formula for the sum of an arithmetic series is given by ( S_n = \frac{n}{2} (a + l) ) or ( S_n = \frac{n}{2} (2a + (n - 1)d) ), where ( S_n ) is the sum of the first ( n ) terms, ( a ) is the first term, ( l ) is the last term, ( d ) is the common difference, and ( n ) is the number of terms. The first formula uses the first and last terms, while the second uses the first term and the common difference.
It is an Arithmetic Progression with a constant difference of 11 and first term 15.
What is the 14th term in the arithmetic sequence in which the first is 100 and the common difference is -4? a14= a + 13d = 100 + 13(-4) = 48
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It is a + 8d where a is the first term and d is the common difference.
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From any term after the first, subtract the preceding term.
For an Arithmetic Progression, Sum = 15[a + 7d].{a = first term and d = common difference} For a Geometric Progression, Sum = a[1-r^15]/(r-1).{r = common ratio }.
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The sum of the first 12 terms of an arithmetic sequence is: sum = (n/2)(2a + (n - 1)d) = (12/2)(2a + (12 - 1)d) = 6(2a + 11d) = 12a + 66d where a is the first term and d is the common difference.
Since there are no graphs following, the answer is none of them.
It is an Arithmetic Progression with a constant difference of 11 and first term 15.
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