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A set of which all the elements are contained in another set. The set of even numbers is a subset of the set of integers.
2 does belong to the set of imaginary numbers. Any real number is also imaginary. Imaginary numbers are the set of all numbers that can be expressed as a +b*i where "i" is the square root of negative one and "a" and "b" are both real numbers.
Z=Integers; Rational numbers={a/b| a,b∈Z, b ≠ 0}.
A set "A" is said to be a subset of of set "B", if every element in set "A" is also an element of set "B". If "A" is a subset of "B" and the sets are not equal, "A" is said to be a proper subset of "B". For example: the set of natural numbers is a subset of itself. The set of square numbers is a subset (and also a proper subset) of the set of natural numbers.
No idea what you're on about. If you are asking in what order do the sets of numbers apear in terms of proving there existence, I believe they are in the following order:N->Z->Q->R->CWhere: N is the set of natural numbers, i.e. whole numbers ranging from 1 to infinity.Z is the set or whole numbers including zero ranging from -infinity to +infinityQ is the set of rational numbers, i.e. the set of numbers that can be expressed in the form a/b where a and b are in Z with b not equal to 0.R is the set or real numbers, the collection of every rational and non rational number.C is the set of complex numbers, i.e. all numbers that can be expressed as a+biwhere a and b are in R and i is the squareroot of -1.
NO. The set of numbers in Set B and the set of numbers in Set C CAN be the same, but are not necessarily so.For example if Set A were "All Prime Numbers", Set B were "All Even Numbers", and Set C were "All numbers that end in '2'", A union B would equal A union C since 2 is the only even prime number and 2 is the only prime number that ends in 2. However, Sets B and C are not the same set since 4 exists in Set B but not Set C, for example.However, we note in this example and in any other possible example that where Set B and Set C are different, one will be a subset of the other. In the example, Set C is a subset of Set B since all numbers that end in 2 are even numbers.
set of all even natural numbers less than 9 Answer = {1,2,3,4,5,6,7,8}
A set of which all the elements are contained in another set. The set of even numbers is a subset of the set of integers.
It is 260.
It is the solution set for that particular inequality.
An ordered set of numbers is a set of numbers in which the order does matter. In ordinary sets {A, B} is the same as {B, A}. However, the ordered set (a, b) is not the same as the ordered set (B, a).
Elements can be an element of a set. Lets say you have a set of numbers like A{2,3,5,8,45,86,9,1} B{2,7,0,100} all those numbers are called elements of that set 2 is an element of set A and B 100 is an element of set B 45 is an element of set A
2 does belong to the set of imaginary numbers. Any real number is also imaginary. Imaginary numbers are the set of all numbers that can be expressed as a +b*i where "i" is the square root of negative one and "a" and "b" are both real numbers.
All even numbers have two as a factor. That means that any set of even numbers will have at least a two as a common factor. Since 2 will be a part of the greatest common factor, it will have to be even.
Z=Integers; Rational numbers={a/b| a,b∈Z, b ≠ 0}.
A set "A" is said to be a subset of of set "B", if every element in set "A" is also an element of set "B". If "A" is a subset of "B" and the sets are not equal, "A" is said to be a proper subset of "B". For example: the set of natural numbers is a subset of itself. The set of square numbers is a subset (and also a proper subset) of the set of natural numbers.
The set of real numbers is a subset of the set of complex numbers. For the set of complex numbers, given in the form (a + bi), where a and b can be any real number, the number is only a real number, if b = 0.