6ab(2x2+x-5)
The GCF is 7x^7.
If that's - 338, the answer is 2(x + 13)(x - 13)
That doesn't factor neatly. Applying the quadratic formula, we find two real solutions: 10 plus or minus 4 times the square root of 7. x = 20.583005244258363 x = -0.5830052442583629
If that's +28, the answer is (x - 4)
2x2+13x+15 = (2x+3)(x+5)
4x4 + 1 = (2x2 - 2x + 1)(2x2 + 2x + 1)
Doesn't factor evenly, use quadratic
2x2 - 5x + 12 does not factor. 2x2 - 5x - 12 factors into (2x + 3)(x - 4) 2x2 + 5x - 12 factors into (2x - 3)(x + 4)
(2x + 1)(x + 4)
(2x + 1)(x + 3)
(2x+4)(x+1)
No. You'd have to use the ABC-formula
The expression cannot be factorised.
2(x + 6)(x + 3)
2(x^2 +2x + 3)
(x + 2)(x^2+4)