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(ax)(ax) = a2 + 2ax + x2
You notice the first two items, 3bx + 3x factorizes into 3x(b+1). And the last two, by +y factorize into y(b+1) . So (b+1) is a common factor, so you can factorize these two into (b+1)(3x+y)
v=vo + at OR v2=vo2+2ax and one more basic one that I'm forgetting...
The centre is (a, a) and the radius is a*sqrt(2).