You notice the first two items, 3bx + 3x factorizes into 3x(b+1). And the last two, by +y factorize into y(b+1) . So (b+1) is a common factor, so you can factorize these two into (b+1)(3x+y)
(3x - y+ 2)(3x + y + 2)
(3x - y)(x + y)(3x - y)(x + y)
(3x + 3y)(x + y) = 3(x + y)2
(3x - y)(3x - 5y) and (2x + 1)(2x + 11)
3x3 - x2y + 12x - 4y = x2*(3x - y) + 4*(3x - y) = (x2 + 4)*(3x - y)
(3x - y)(3x - y)
(3x - y+ 2)(3x + y + 2)
(3x - y)(x + y)(3x - y)(x + y)
(3x + 3y)(x + y) = 3(x + y)2
9x^2-6xy+y^2 = (y-3x)^2 (y-3x)^2-81 -> ((y-3x)+9)((y-3x)-9)
21-7y+3x-xy7(3-y)+x(3-y)
(3x - y)(3x - 5y) and (2x + 1)(2x + 11)
9x2 - 6xy + y2 - 81 = (3x - y)2 - 81 = (3x - y - 9)*(3x - y + 9)
3x3 - x2y + 12x - 4y = x2*(3x - y) + 4*(3x - y) = (x2 + 4)*(3x - y)
(3x + 3y)(x + y) or 3(x + y)2
To factorize xy + 3x, we first need to factor out the common factor, which is x. This gives us x(y + 3). Therefore, the factorized form of xy + 3x is x(y + 3).
(x + 2)(y - 3)