(a + b+ c)3 = a3 + b3 + c3 + 3a2b + 3ab2 + 3b2c + 3bc2 + 3c2a + 3ca2 + 6abc
a3+b3=(a+b)3-3a2b-3ab2
(a + b)3 = a3 + 3a2b + 3ab2 + b3
3a3b + 12a2b2 + 9a5b3 = 3a2b (a + 4b + 3a3b2)
a3+b3+c3+3a2b+3a2c+3b2c+3ab2+3ac2+3bc2+6abc
(a^2 + 8b)(a^2 - 5b)
3a2b(2b2-1)
(a + b+ c)3 = a3 + b3 + c3 + 3a2b + 3ab2 + 3b2c + 3bc2 + 3c2a + 3ca2 + 6abc
do you mean 12a3 - 5a2b - 2b2 ?? = 12a3 + 8a2b - 3a2b - 2b2 then group 1st 2 terms and last 2 and use GCF = (12a3 + 8a2b) + ( - 3a2b - 2b2) = 4a2(3a + 2b) + (-b)(3a2 +2b) not much help, but that's all folks
3a2b
5
(a + b)3 = a3 + 3a2b + 3ab2 + b3
a3+b3=(a+b)3-3a2b-3ab2
(a + b)3 = a3 + 3a2b + 3ab2 + b3
3a3b + 12a2b2 + 9a5b3 = 3a2b (a + 4b + 3a3b2)
Consider a binomial (a+b). The cube of the binomial is given as =(a+b)3 =a3 + 3a2b + 3ab2 + b3.
a3+b3+c3+3a2b+3a2c+3b2c+3ab2+3ac2+3bc2+6abc