a3+b3+c3+3a2b+3a2c+3b2c+3ab2+3ac2+3bc2+6abc
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b+b+b+c+c+c+c =3b+4c
(a+b-c)2 = a2 + b2 +c2 +2ab - 2bc - 2ac
(a + b+ c)3 = a3 + b3 + c3 + 3a2b + 3ab2 + 3b2c + 3bc2 + 3c2a + 3ca2 + 6abc
2b + 2c or 2(b + c)
And how does this relate to coins?