-2x - 2 = 4-2x = 4 + 2-2x = 6x = 6/-2x = -3Check:-2(-3) - 2 = 46 - 2 = 44 = 4
2x + 4 = 2 2x = -2 x = -1
Divide both sides by two. x = 2 2x=4 2x/2=4/2 2x/2=1x=x 4/2=2 x=2
-2x - 10 + 4 = 2 -2x - 6 = 2 -2x = 2 + 6 -2x = 8 -x = 8 / 2 x = -4 Check: -2(-4) - 10 + 4 = 2 8 - 10 + 4 = 2 8 - 6 = 2 2 = 2
Do you mean '16x^(4) -1 ; or ' (16 X 4 ) - 1' . Reason , the answers will be different. 16x^(4) - 1 = (2x)^(4) - 1^(4) = ((2x^(2) - 1^(2))((2x)^(2) + 1^(2)) = (2x - 1)(2x +1)((2x)^(2) + 1^(2)) = (2x - 1)(2x + 1)((2x)^(2) + 1) 2 & ( 16 X 4 ) - 1) = 64 - 1 = 63
2x + 4 = 2(x + 2)
2x+4=30 (1.) Subtract 4 from both side 2x+4=30 -4 -4 2x =26 (2.) Divide 2 from 2x and 30 (2x/2, 26/2) x =13
2x * 2x (2*2=4) therefore, 2x*2x equals 4x2.
(x2+3x-4) (x-4)
Here is how you solve this problem... 5x*4-3x*5*2x-9= (Combine like-terms) 5x-3x*2x= 2x*2x=(2x)2 (Add the rest of the problem) (2x)2*4*5-9=(2x)2*20-9 (2x)2*11 (2x)2 *11= your answer
3x - 2 = 2x + 4 3x - 2x = 4 + 2 x = 6
4+2x=9 -4 -4 2x=9 2x/2 9/2 x=4 1/2
If: y = x^2 -2x +4 and y = 2x^2 -4x +4 Then: 2x^2 -4x +4 = x^2 -2x +4 Transposing terms: x^2 -2x = 0 Factorizing: (x-2)(x+0) => x = 2 or x = 0 Therefore by substitution points of intersect are at: (2, 4) and (0, 4)
2(x + 2)(x - 2)(x2 + 2x + 4)(x2 - 2x + 4)
9x-5x-2x = -4 2x = -4 x = -2
x^2 = 2x -15x^2 - 2x + 15 = 0 where a = 1, b = -2, and c = 15x = [-b ± √[b^2 - 4(a)(c)]]/2ax = [2 ± √[2^2 - 4(1)(15)]]/[2(1)]x = [2 ± √(4 - 60)]/2x = [2 ± √(- 56)]/2x = (2 ± i√56)/2x = (2 ± 2i√14)/2x = 1 ± i√14
If you mean 2x+4(7x-1) then 2x+28x-4=30x-4=2(15x-2) If you mean 2x+4(7x)-1 then 2x+28x-1=30x-1