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Earn +20 ptsQ: What is the answer to 4 (2x -1)?
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16x4 - 1 equals?
Do you mean '16x^(4) -1 ; or ' (16 X 4 ) - 1' . Reason , the answers will be different. 16x^(4) - 1 = (2x)^(4) - 1^(4) = ((2x^(2) - 1^(2))((2x)^(2) + 1^(2)) = (2x - 1)(2x +1)((2x)^(2) + 1^(2)) = (2x - 1)(2x + 1)((2x)^(2) + 1) 2 & ( 16 X 4 ) - 1) = 64 - 1 = 63
What is 2x-1 plus 2x-1 plus 2x-1 plus 2x-1?
8x-4
What is the answer to 2x plus 4 2?
2x + 4 = 2 2x = -2 x = -1
4 plus 2x- -2x plus 1 equals 13 plus 6?
(4 + 2x) - (-2x + 1) = 13 + 6 4 + 2x + 2x -1 = 19 4x +3 = 19 4x = 19 - 3 4x = 16 therefore x = 16/4 x = 4
How do you integrate of e power 2x plus e power minus 2x?
int[e(2X) +e(- 2X)] integrate term by term 1/22 e(2X) - 1/22 e(- 2X) + C (1/4)e(2X) - (1/4)e(- 2X) + C ====================
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