Do you mean '16x^(4) -1 ; or ' (16 X 4 ) - 1' . Reason , the answers will be different. 16x^(4) - 1 = (2x)^(4) - 1^(4) = ((2x^(2) - 1^(2))((2x)^(2) + 1^(2)) = (2x - 1)(2x +1)((2x)^(2) + 1^(2)) = (2x - 1)(2x + 1)((2x)^(2) + 1) 2 & ( 16 X 4 ) - 1) = 64 - 1 = 63
8x-4
(4 + 2x) - (-2x + 1) = 13 + 6 4 + 2x + 2x -1 = 19 4x +3 = 19 4x = 19 - 3 4x = 16 therefore x = 16/4 x = 4
2x + 4 = 2 2x = -2 x = -1
int[e(2X) +e(- 2X)] integrate term by term 1/22 e(2X) - 1/22 e(- 2X) + C (1/4)e(2X) - (1/4)e(- 2X) + C ====================
Do you mean '16x^(4) -1 ; or ' (16 X 4 ) - 1' . Reason , the answers will be different. 16x^(4) - 1 = (2x)^(4) - 1^(4) = ((2x^(2) - 1^(2))((2x)^(2) + 1^(2)) = (2x - 1)(2x +1)((2x)^(2) + 1^(2)) = (2x - 1)(2x + 1)((2x)^(2) + 1) 2 & ( 16 X 4 ) - 1) = 64 - 1 = 63
If you mean 2x+4(7x-1) then 2x+28x-4=30x-4=2(15x-2) If you mean 2x+4(7x)-1 then 2x+28x-1=30x-1
4 + 32x3 = 4*(1 + 8x3) = 4*(1 + 2x)*(1 - 2x + 4x2) which cannot be factorised further.
If 3X - 4 ------ = 0 1-2X-4 So 3X - 4 ----- = 0 [ x (2X-3) ] 2X-3 3X-4 = 2X-3 [ -2X ] X - 4 = -3 [ +4 ] X= 1
4x + 1 = 2x + 5 Subtract '1' frp, bpth sides Hence 4x = 2x + 4 Subtract '2x' from botbh sides 2x = 4 Divide both sides by '2' x = 2 The answer!!!!!!
8x-4
2x-4y=4 -4y=-2x+4 y=1/2x-1 Slope is 1/2 (.5)
(3x+1)(2x+4) = 6x2+4+2x+12x = 6x2+14x+4
(4 + 2x) - (-2x + 1) = 13 + 6 4 + 2x + 2x -1 = 19 4x +3 = 19 4x = 19 - 3 4x = 16 therefore x = 16/4 x = 4
2x + 4 = 2 2x = -2 x = -1
-3
4x2 + 8x + 4 = 4 (x2 + 2x + 1) = 4 (x + 1)2