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5x3-3x plus 4 -3x3-2x2 plus 6x-1?
Am I right :P?5x^(3)-3x+4-3x^(3)-2x+6x-1Since 5x^(3) and -3x^(3) are like terms, add -3x^(3) to 5x^(3) to get 2x^(3).(d)/(dx) 5x^(3)-3x+4-3x^(3)-2x+6x-1=2x^(3)-3x+4-2x+6x-1Since -3x and -2x are like terms, subtract 2x from -3x to get -5x.(d)/(dx) 5x^(3)-3x+4-3x^(3)-2x+6x-1=2x^(3)-5x+4+6x-1Since -5x and 6x are like terms, subtract 6x from -5x to get x.(d)/(dx) 5x^(3)-3x+4-3x^(3)-2x+6x-1=2x^(3)+x+4-1Subtract 1 from 4 to get 3.(d)/(dx) 5x^(3)-3x+4-3x^(3)-2x+6x-1=2x^(3)+x+3To find the derivative of 2x^(3), multiply the base (x) by the exponent (3), then subtract 1 from the exponent.(d)/(dx) 5x^(3)-3x+4-3x^(3)-2x+6x-1=6x^(2)+(d)/(dx) x+3To find the derivative of x, multiply the base (x) by the exponent (1), then subtract 1 from the exponent (1-1=0). Since the exponent is now 0, x is eliminated from the term.(d)/(dx) 5x^(3)-3x+4-3x^(3)-2x+6x-1=6x^(2)+1+(d)/(dx) 3Since 3 does not contain x, the derivative of 3 is 0.(d)/(dx) 5x^(3)-3x+4-3x^(3)-2x+6x-1=6x^(2)+1+0Add 0 to 1 to get 1.(d)/(dx) 5x^(3)-3x+4-3x^(3)-2x+6x-1=6x^(2)+1The derivative of 5x^(3)-3x+4-3x^(3)-2x+6x-1 is 6x^(2)+1.6x^(2)+1
What is the solution to 8x-19 equals 3x plus 1?
8x - 19 = 3x + 1 5x -19 = 1 5x = 20 x = 4
What is 3x to second power over 12x to sixth power in lowest terms?
(3x)2/(12x)6(3x)2=32x2=9x2(12x)6=126x6=2985984x6(3x)2/(12x)6=9x2/2985984x69/2985984=1/331776.x2/x6=x2 * x-6=x-4=1/x4.9x2/2985984x6=1/331776 * 1/x4=1/331776x4
How do you factor 5x2 - 12x 4?
assuming you meant 5x2+12x+4 (5x+2)(x+2)
What is the answer 3x divided 5-x divided 3 equals 4?
3x/(5-x)/3=4 3x/(5-x)=4X3 3x=12(5-x) 3x=60-12x 3x+12x=60 x=4
What equals to 4x 5x 3x?
If you're adding them, that equals 12x
3x-8 plus 5x plus 39 plus 4 x plus 51 equals?
3x-8+5x+39+4x+51 = x(3+5+4) + -8 + 39 + 51 = 12x +82
How do you distribute 3x(x-4)?
3x * (x - 4) = 3x*x - 3x*4 = 3x^2 - 12x.
How do you solve 5x-2 3x-6?
5x-2 = 3x-6 5x = 3x - 6 +2 5x = 3x - 4 5x - 3x = -4 2x = -4 x = -2
5x3-3x plus 4 -3x3-2x2 plus 6x-1?
Am I right :P?5x^(3)-3x+4-3x^(3)-2x+6x-1Since 5x^(3) and -3x^(3) are like terms, add -3x^(3) to 5x^(3) to get 2x^(3).(d)/(dx) 5x^(3)-3x+4-3x^(3)-2x+6x-1=2x^(3)-3x+4-2x+6x-1Since -3x and -2x are like terms, subtract 2x from -3x to get -5x.(d)/(dx) 5x^(3)-3x+4-3x^(3)-2x+6x-1=2x^(3)-5x+4+6x-1Since -5x and 6x are like terms, subtract 6x from -5x to get x.(d)/(dx) 5x^(3)-3x+4-3x^(3)-2x+6x-1=2x^(3)+x+4-1Subtract 1 from 4 to get 3.(d)/(dx) 5x^(3)-3x+4-3x^(3)-2x+6x-1=2x^(3)+x+3To find the derivative of 2x^(3), multiply the base (x) by the exponent (3), then subtract 1 from the exponent.(d)/(dx) 5x^(3)-3x+4-3x^(3)-2x+6x-1=6x^(2)+(d)/(dx) x+3To find the derivative of x, multiply the base (x) by the exponent (1), then subtract 1 from the exponent (1-1=0). Since the exponent is now 0, x is eliminated from the term.(d)/(dx) 5x^(3)-3x+4-3x^(3)-2x+6x-1=6x^(2)+1+(d)/(dx) 3Since 3 does not contain x, the derivative of 3 is 0.(d)/(dx) 5x^(3)-3x+4-3x^(3)-2x+6x-1=6x^(2)+1+0Add 0 to 1 to get 1.(d)/(dx) 5x^(3)-3x+4-3x^(3)-2x+6x-1=6x^(2)+1The derivative of 5x^(3)-3x+4-3x^(3)-2x+6x-1 is 6x^(2)+1.6x^(2)+1
What is the factor of 9x2 minus 12x minus 4?
There's a chance this was notated incorrectly. It looks like it wants to be some combination of 3x and 2. 9x2 + 12x + 4 = (3x + 2)(3x + 2) or (3x + 2)2 -9x2 - 12x - 4 = -(3x + 2)2 9x2 - 12x + 4 = (3x - 2)2 -9x2 + 12x - 4 = -(3x - 2)2
How do you do (3x 4)2?
3x * (x - 4) = 3x*x - 3x*4 = 3x^2 - 12x.
What is 3x plus 1 times 2x plus 4?
(3x+1)(2x+4) = 6x2+4+2x+12x = 6x2+14x+4
What is the solution to 8x-19 equals 3x plus 1?
8x - 19 = 3x + 1 5x -19 = 1 5x = 20 x = 4
Factor 9x2 plus 12x plus 4?
9x2 + 12x + 4 = 9x2 + 6x + 6x + 4 = 3x(3x + 2) + 2(3x + 2) = (3x + 2)(3x + 2) = (3x + 2)2
What is answer to 5x-4 equals 3x plus 6 equals?
5x - 4 = 3x + 6 5x - 3x = 6 + 4 2x = 10 x = 5
Is the degree of the polynomial 3x4 plus 4x3 - 3x4 plus 5x plus 1 is 3 true or false?
True.3x^4 + 4x^3 - 3x^4 + 5x + 1= 4x^3 + 5x + 1
