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9x2 plus 12x plus 4 factored in decending order?
9x2...I guess that means 9x squared ? The problem: 9x(squared)+12x+4 Here's the answer: (3x+2)(3x+2) or even more simplified: (3x+2) squared
What is the factor of 9x squared-1?
10
3x squared in parentheses to the negative 2nd power?
That is 1/9x2
9 x squared plus 3 x divided by 3 x?
9x2 + 3x / 3x equals (3x + 1).9x2 + 3x divided by x is 9x + 3 , and then divided by 3 yields the 3x +1.
What is the answer to 9x squared minus 9x minus 10?
9x2-9x-10 = (3x+2)(3x-5) when factored
9x2 plus 12x plus 4 factored in decending order?
9x2...I guess that means 9x squared ? The problem: 9x(squared)+12x+4 Here's the answer: (3x+2)(3x+2) or even more simplified: (3x+2) squared
What is the factor of 9x squared-1?
10
3x squared in parentheses to the negative 2nd power?
That is 1/9x2
How do you factor 9x squared plus 6x plus 1?
9x2 + 6x + 1 = 9x2 + 3x + 3x + 1 = 3x(3x + 1) + 1(3x + 1) = (3x + 1)(3x + 1) or (3x +1)2
9 x squared plus 3 x divided by 3 x?
9x2 + 3x / 3x equals (3x + 1).9x2 + 3x divided by x is 9x + 3 , and then divided by 3 yields the 3x +1.
What is the answer to 9x squared minus 9x minus 10?
9x2-9x-10 = (3x+2)(3x-5) when factored
How do you factor 18X squared plus 2?
18x2 + 2= 2(9x2 + 1)= 2(9x2 - -1)= 2[(3x)2 - i2]= 2(3x + √-1)(3x - √-1) (substitute i for √-1)= 2(3x + i)(3x - i)
What is 9x squared minus 6xy plus y squared minus 81 factored as?
9x2 - 6xy + y2 - 81 = (3x - y)2 - 92 = (3x - y - 9)(3x - y + 9)
What are the factors of 9x2 3x-2?
If you mean: 9x2+3x-2 = (3x+2)(3x-1) when factored
Factor 9x squared minus 6xy plus y squared minus 81?
9x2 - 6xy + y2 - 81 = (3x - y)2 - 81 = (3x - y - 9)*(3x - y + 9)
Factor 9x2 plus 12x plus 4?
9x2 + 12x + 4 = 9x2 + 6x + 6x + 4 = 3x(3x + 2) + 2(3x + 2) = (3x + 2)(3x + 2) = (3x + 2)2
How do you factor 9x squared plus 25?
9x2 + 25 has no rational factors. Its factorisation in the complex domain is:(3x + 5i)*(3x - 5i) where i is the imaginary square root of -1.
