you know that:
Area=length x width
Area=A=30 cm2
and that the width= w
and that the length= 2w
so, what you do is:
30=2w*w (solve for w)
30=2w2
15=w2
take the square root of 15=w
w=3.87cm
Your width is 3.87cm
your length is 2(3.87)=7.75cm
To find the width of the rectangle, we need to subtract twice the length from the perimeter. Given that the length is 25 centimeters and the perimeter is 84 centimeters, twice the length would be 50 centimeters. Subtracting 50 from 84 gives us a width of 34 centimeters for the rectangle.
the length of a rectangle is 8 more than the width. the area os 345 centimeters. find the length and width of the rectangle
The length is (18 centimeters) minus (the width)
Twice (length + width)
For a rectangle, calculate twice the length, plus twice the width.For a rectangle, calculate twice the length, plus twice the width.For a rectangle, calculate twice the length, plus twice the width.For a rectangle, calculate twice the length, plus twice the width.
The width is 6 cm and the length is 12 cm.
To find the width of the rectangle, we need to subtract twice the length from the perimeter. Given that the length is 25 centimeters and the perimeter is 84 centimeters, twice the length would be 50 centimeters. Subtracting 50 from 84 gives us a width of 34 centimeters for the rectangle.
The length of a rectangle is twice its width. If the perimeter of the rectangle is , find its area.
2(2x) +2x = 100
the length of a rectangle is 8 more than the width. the area os 345 centimeters. find the length and width of the rectangle
4 cm
2x4
The length is (18 centimeters) minus (the width)
Twice (length + width)
In a rectangle, the area is calculated by multiplying length x width. If (for example) both length and width are in centimeters, the area will be in square centimeters.
30 ft
For a rectangle, calculate twice the length, plus twice the width.For a rectangle, calculate twice the length, plus twice the width.For a rectangle, calculate twice the length, plus twice the width.For a rectangle, calculate twice the length, plus twice the width.