Q: What is the area of a rectangle with the dimensions of 40 by 14?

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4 x 10

2 sides = 40 feet long, 2 sides = 26 feet long and an area of 1,040 square feet.

the area of a rectangleis 100 square inches. The perimeter of the rectangle is 40 inches. A second rectangle has the same area but a different perimeter. Is the secind rectangle a square? Explain why or why not.

yes

40

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4 x 10

Area of RECTANGLE =length * breadth[width] m*m =40*14 m*m 560m*m

2 sides = 40 feet long, 2 sides = 26 feet long and an area of 1,040 square feet.

The dimensions work out as: length = 30 times the square root of 5 breadth = 40 times the square root of 5 check: (30 times sq rt of 5)*(40 times sq rt of 5) = 6000 square units

the perimeter of a rectangle is 700 yards. what are the dimensions of the rectangle if the lenght is 80 yards more than the width?

The diagonal is 47.707'

the area of a rectangleis 100 square inches. The perimeter of the rectangle is 40 inches. A second rectangle has the same area but a different perimeter. Is the secind rectangle a square? Explain why or why not.

If it's the dimensions of a rectangle then by using Pythagoras' theorem its diagonal is 40

8m*5m=40 m2 The area of the rectangle is 40m2

Area rectangle: 20 times 40 = 800 square inches

A square cannot measure 90 by 40; this would be a rectangle. Anyway, the area of this rectangle is 90 x 40 = 3,600 square units.

The answer is 40 (cm?). 6 + 6 (both sides) +14+14= 40