To find the area multiply the length by the width, in this case 40 x 14 = 560 square units (units being inches, feet, centimetres, metres etc.)
4 x 10
2 sides = 40 feet long, 2 sides = 26 feet long and an area of 1,040 square feet.
The area model for multiplying 9 by 43 involves breaking down the numbers into more manageable parts. You can decompose 43 into 40 and 3, creating two rectangles: one with dimensions 9 and 40, and the other with dimensions 9 and 3. The area of the first rectangle is 360 (9 x 40) and the area of the second rectangle is 27 (9 x 3). Adding these two areas together, 360 + 27, gives a total area of 387, which is the product of 9 and 43.
To draw a rectangle with an area of 36 cm² and a perimeter of 40 cm, you first need to determine the dimensions. The area ( A ) is given by ( A = length \times width ), so ( lw = 36 ). The perimeter ( P ) is given by ( P = 2(length + width) ), so ( 2(l + w) = 40 ), which simplifies to ( l + w = 20 ). Solving these equations, you find that the dimensions are 18 cm (length) and 2 cm (width) or vice versa. You can then use these measurements to draw the rectangle.
the area of a rectangleis 100 square inches. The perimeter of the rectangle is 40 inches. A second rectangle has the same area but a different perimeter. Is the secind rectangle a square? Explain why or why not.
4 x 10
Area of RECTANGLE =length * breadth[width] m*m =40*14 m*m 560m*m
2 sides = 40 feet long, 2 sides = 26 feet long and an area of 1,040 square feet.
The dimensions work out as: length = 30 times the square root of 5 breadth = 40 times the square root of 5 check: (30 times sq rt of 5)*(40 times sq rt of 5) = 6000 square units
the perimeter of a rectangle is 700 yards. what are the dimensions of the rectangle if the lenght is 80 yards more than the width?
The area model for multiplying 9 by 43 involves breaking down the numbers into more manageable parts. You can decompose 43 into 40 and 3, creating two rectangles: one with dimensions 9 and 40, and the other with dimensions 9 and 3. The area of the first rectangle is 360 (9 x 40) and the area of the second rectangle is 27 (9 x 3). Adding these two areas together, 360 + 27, gives a total area of 387, which is the product of 9 and 43.
The diagonal is 47.707'
To draw a rectangle with an area of 36 cm² and a perimeter of 40 cm, you first need to determine the dimensions. The area ( A ) is given by ( A = length \times width ), so ( lw = 36 ). The perimeter ( P ) is given by ( P = 2(length + width) ), so ( 2(l + w) = 40 ), which simplifies to ( l + w = 20 ). Solving these equations, you find that the dimensions are 18 cm (length) and 2 cm (width) or vice versa. You can then use these measurements to draw the rectangle.
The rectangle has Length = 16 cm and Width = 4 cm.Perimeter = 2L + 2W = 2(16) + 2(4) = 32 + 8 = 40 cmArea = L W = 16 x 4 = 64 cm2
the area of a rectangleis 100 square inches. The perimeter of the rectangle is 40 inches. A second rectangle has the same area but a different perimeter. Is the secind rectangle a square? Explain why or why not.
8m*5m=40 m2 The area of the rectangle is 40m2
Area rectangle: 20 times 40 = 800 square inches