To find the area multiply the length by the width, in this case 40 x 14 = 560 square units (units being inches, feet, centimetres, metres etc.)
4 x 10
2 sides = 40 feet long, 2 sides = 26 feet long and an area of 1,040 square feet.
the area of a rectangleis 100 square inches. The perimeter of the rectangle is 40 inches. A second rectangle has the same area but a different perimeter. Is the secind rectangle a square? Explain why or why not.
To draw a rectangle with an area of 36 cm² and a perimeter of 40 cm, you first need to determine the dimensions. The area ( A ) is given by ( A = length \times width ), so ( lw = 36 ). The perimeter ( P ) is given by ( P = 2(length + width) ), so ( 2(l + w) = 40 ), which simplifies to ( l + w = 20 ). Solving these equations, you find that the dimensions are 18 cm (length) and 2 cm (width) or vice versa. You can then use these measurements to draw the rectangle.
To find the area of a rectangle with a length of 10 cm and a width of 4 cm, you multiply the two dimensions. The area is calculated as follows: Area = length × width = 10 cm × 4 cm = 40 cm². Therefore, the area is 40 square centimeters.
4 x 10
Area of RECTANGLE =length * breadth[width] m*m =40*14 m*m 560m*m
2 sides = 40 feet long, 2 sides = 26 feet long and an area of 1,040 square feet.
The dimensions work out as: length = 30 times the square root of 5 breadth = 40 times the square root of 5 check: (30 times sq rt of 5)*(40 times sq rt of 5) = 6000 square units
the perimeter of a rectangle is 700 yards. what are the dimensions of the rectangle if the lenght is 80 yards more than the width?
The diagonal is 47.707'
the area of a rectangleis 100 square inches. The perimeter of the rectangle is 40 inches. A second rectangle has the same area but a different perimeter. Is the secind rectangle a square? Explain why or why not.
8m*5m=40 m2 The area of the rectangle is 40m2
To draw a rectangle with an area of 36 cm² and a perimeter of 40 cm, you first need to determine the dimensions. The area ( A ) is given by ( A = length \times width ), so ( lw = 36 ). The perimeter ( P ) is given by ( P = 2(length + width) ), so ( 2(l + w) = 40 ), which simplifies to ( l + w = 20 ). Solving these equations, you find that the dimensions are 18 cm (length) and 2 cm (width) or vice versa. You can then use these measurements to draw the rectangle.
If it's the dimensions of a rectangle then by using Pythagoras' theorem its diagonal is 40
Oh, dude, you're hitting me with the math questions, huh? So, like, if the perimeter is 40 cm, that means the sum of all the sides is 40 cm. And if the area is 64 cm², that's like the space inside the rectangle. You can totally use those two pieces of info to find the dimensions of the rectangle, but like, I'm not gonna do the math for you.
Area rectangle: 20 times 40 = 800 square inches