To draw a rectangle with an area of 36 cm² and a perimeter of 40 cm, you first need to determine the dimensions. The area ( A ) is given by ( A = length \times width ), so ( lw = 36 ). The perimeter ( P ) is given by ( P = 2(length + width) ), so ( 2(l + w) = 40 ), which simplifies to ( l + w = 20 ). Solving these equations, you find that the dimensions are 18 cm (length) and 2 cm (width) or vice versa. You can then use these measurements to draw the rectangle.
Length = 9 Width = 9 Your rectangle is a square.
It is: 12 units in length
It is a 3 x 15 rectangle !
To find the smallest perimeter of a rectangle with an area of 36 cm², we use the relationship between area and perimeter. The area ( A = l \times w ) (length times width) should equal 36 cm². For a given area, a square shape minimizes the perimeter, so if both length and width are equal, each side would be ( \sqrt{36} = 6 ) cm. Thus, the smallest perimeter is ( P = 2(l + w) = 2(6 + 6) = 24 ) cm.
If you restrict yourself to integers, it could be 36, 60 or 164 in. If it was a square, it would have to be 36.
how do you find the area of a rectangle witha perimeter of 36 in You don't. You need more information For example a 1 x 17 rectangle has a perimeter of 36 and its area is 17. But a 2 x 16 rectangle also has a perimeter of 36 and its area is 32.
Draw the table and calculate the area of the triangle the area of a square is 36
Perimeter is 36 mArea is 72 square m
The perimeter doesn't tell you the area. There are an infinite number of differentareas that it could have.-- If it's a circle with a perimeter of 36, then the area is 103.1324. (rounded)-- If it's a square with a perimeter of 36, then the area is 81 .-- If it's a rectangle with a perimeter of 36, then the area can be any numberthat's more than zero and less than 81 .
Length = 9 Width = 9 Your rectangle is a square.
It is: 12 units in length
81 square feet.
It is a 3 x 15 rectangle !
To find the smallest perimeter of a rectangle with an area of 36 cm², we use the relationship between area and perimeter. The area ( A = l \times w ) (length times width) should equal 36 cm². For a given area, a square shape minimizes the perimeter, so if both length and width are equal, each side would be ( \sqrt{36} = 6 ) cm. Thus, the smallest perimeter is ( P = 2(l + w) = 2(6 + 6) = 24 ) cm.
The rectangle has a length of 12 cm and a width of 3 cm.
Length of rectangle is 18 units and its width is 2 units
If you restrict yourself to integers, it could be 36, 60 or 164 in. If it was a square, it would have to be 36.