3√3/2 sq in ≈ 2.6 sq in
By joining opposite vertices of the hexagon with diagonals, the hexagon is divided up into 6 equilateral triangles, each of side 1 in
Area_hexagon = 6 x area_equilateral_triangle
= 6 x 1/2 x side x height
= 6 x 1/2 x side x (sin 60o x side)
= 6 x 1/2 x (√3/2) x side2
= 3√3/2 x side2
= 3√3/2 x (1 in)2
= 3√3/2 sq in
≈ 2.6 sq in
The area of a regular hexagon with a 24-inch perimeter is about 41.57 square inches.
The area is 96*sqrt(3) = 166.3 sq inches, approx.
If it is a regular 6 sided hexagon then its perimeter is 6 times 12 = 72 inches
Area = 2.598 sq inches, approx.
P = 6(5/8 inches) =
The area of a regular hexagon with a 24-inch perimeter is about 41.57 square inches.
Each side of a regular hexagon is the same as its radius - in this case 31 inches.
The area is 96*sqrt(3) = 166.3 sq inches, approx.
0.64952
If it is a regular 6 sided hexagon then its perimeter is 6 times 12 = 72 inches
Area = 2.598 sq inches, approx.
P = 6(5/8 inches) =
Hexagon is composed of 6 equilateral triangles of side 12in, or 12 right-angled triangles, in this case with sides 6, 12 and 19. Two of these make a rectangle 6 x 19 ie 114 sqin. there are 6 such rectangles so the total area is 684 sqin. The only problem is that no such hexagon is possible, as the side must be greater than the apothem to satisfy Pythagoras?
This hexagon is made of 6 equilateral trianges of side length 8 inches. Height of such a triangle is SQRT(8^2 - 4^2) = SQRT(48) = 6.93 inches. Area of one triangle = 4 x 6.93 = 27.71 square inches. Answer = 6 * 27.71 = 166.28 square inches
No problem in a hexagon, for example.
24 inches
A square inch does not have a specific number of inches in it because a square inch is a unit of area, not length. It represents the area of a square with sides that are each 1 inch long.