Tough to do this without a picture but here goes... Assuming the 4 semi-circles come right out of the corners of the square, they would be equal to two circles with diameters of 15cm apiece and radii of 7.5
The area of the square is 15 x 15 = 225 sq. cm
The area of the circles is 2 (pi x 56.25)
225 + 353.43 = 578.43 sq. cm
sqrt(15) = 3.873 cm (approx)
Using Pythagoras' theorem: 15 times the square root of 2 cm in length
it is 60cm
The perimeter of a square is any side times 4 since all 4 sides are equal. In this case it is 15 *4 cm or 60 cm.
15cm
sqrt(15) = 3.873 cm (approx)
Using Pythagoras' theorem: 15 times the square root of 2 cm in length
15*15 = 225 square centimetres.
it is 60cm
The perimeter of a square is any side times 4 since all 4 sides are equal. In this case it is 15 *4 cm or 60 cm.
Let x be the length of one of the congruent sides, then the three sides are x, x, 3x. Perimeter = x + x + 3x = 5x = 75cm => x = 15cm Thus the three sides are 15cm, 15cm, 45cm.
The perimetre is 60cm.Because a perfect square has equal sides, which are in length the square root of the area because multiplying the length of a square by itself gives it's area. So:sqrt(225) = 15cmA square has 4 sides of the same length, so if 1 side is 15cm all 4 sides that form the perimetre must be 15*4=60cm.
Isosceles
225 cm squared
60 cm2
Perimeter is the total of all the sides. Let's assume your part-question relates to a rectangle. Four sides: 2 x 8cm and 2 x 15cm. I'm sure you can work it out from there...
Perimeter = 8*15 = 120 cm