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How many square feet are in an 18' by 22' by 16' triangle?
I assume you want the area of a triangle with side lengths 18 ft, 22 ft and 16 ft. Given the sides of a triangle, its area is given by: area = √(s(s - a)(s - b)(s - c)) Where s is the semi-perimeter, ie s = ½(a + b + c) or triangle with sides 18 ft, 22 ft 16 ft, area is: s = ½(18 + 22 + 16) ft = 28 ft → area = √(28(28 - 18)(28 - 22)(28 - 16)) ft² = √3360 ft² ≈ 57.97 ft²
If the base of an isosceles triangle is 22 and the height is 28 how do you figure out the area?
area of a triangle is half the base times the height .5*22*28=308
What is the area of an isosceles triangle with two sides that measure 22 and a base that measures 5?
If the two equal sides are each 22 units in length then using Pythagoras' theorem to find its height it works out as: 54.644 square units rounded to 3 d.p.
The measures of two sides of a triangle are 22 and 34 Which measure is possible for the third side?
Doesn't it depend on what type of triangle it is? And which sides you are measuring? And which side it's laying on?
A triangle has sides of lengths 6 2 and 7 is it a right triangle?
No. For a right angle triangle, the sum of the squares of the shorter sides equals the square of the longer side (the hypotenuse): 22 + 62 = 40 72 = 49
What is the area of 22 40 45?
Assuming these are three sides of a triangle, the area is approx 440 square units.
How many square feet are in an 18' by 22' by 16' triangle?
I assume you want the area of a triangle with side lengths 18 ft, 22 ft and 16 ft. Given the sides of a triangle, its area is given by: area = √(s(s - a)(s - b)(s - c)) Where s is the semi-perimeter, ie s = ½(a + b + c) or triangle with sides 18 ft, 22 ft 16 ft, area is: s = ½(18 + 22 + 16) ft = 28 ft → area = √(28(28 - 18)(28 - 22)(28 - 16)) ft² = √3360 ft² ≈ 57.97 ft²
If the base of an isosceles triangle is 22 and the height is 28 how do you figure out the area?
area of a triangle is half the base times the height .5*22*28=308
What is the area of an isosceles triangle with two sides that measure 22 and a base that measures 5?
If the two equal sides are each 22 units in length then using Pythagoras' theorem to find its height it works out as: 54.644 square units rounded to 3 d.p.
The measures of two sides of a triangle are 22 and 34 Which measure is possible for the third side?
Doesn't it depend on what type of triangle it is? And which sides you are measuring? And which side it's laying on?
A triangle has sides of lengths 6 2 and 7 is it a right triangle?
No. For a right angle triangle, the sum of the squares of the shorter sides equals the square of the longer side (the hypotenuse): 22 + 62 = 40 72 = 49
What is the base measurement of a triangle of a area that is 30m and 10m?
22
How much greater is the surface area of a cube with a side of 10 centimeters than a cube with a side of 5 centimeters?
Ratio of sides = 10/5 = 2 So ratio of surface area = 22= 4Ratio of sides = 10/5 = 2 So ratio of surface area = 22= 4Ratio of sides = 10/5 = 2 So ratio of surface area = 22= 4Ratio of sides = 10/5 = 2 So ratio of surface area = 22= 4
Can you form a triangle with 20 22 and 24?
Yes, you can form a triangle with the lengths 20, 22, and 24. According to the triangle inequality theorem, the sum of the lengths of any two sides must be greater than the length of the third side. In this case, 20 + 22 > 24, 20 + 24 > 22, and 22 + 24 > 20 are all true, confirming that these lengths can indeed form a triangle.
What is the area of a triangle with the base of 12 and height of 22?
132 according to siri
If a triangle has an area 88 and length 14 minus the height what is the height?
the height has to be 22
What is the base measurement of a triangle with an area of 30 m2 and a height of 10 m?
22
