A triangle with side a: 13, side b: 14, and side c: 15 units has an area of 84 square units.
Area = 0.5*5*12 = 30 square units
(13x9) / 2 Length times width. Divide by 2
0 Zero
Area = 1/2*13*height = 104 Multiply both sides by 2: 13*height = 208 Divide both sides by 13: height = 16 inches Check: 1/2*13*16 = 104 square inches
Yes. The triangle with sides 7 cm, 8 cm, 13 cm is obtuse (the angle opposite the side of 13 cm is 120o) and scalene as none of the sides are equal.
Area = 0.5*5*12 = 30 square units
(13x9) / 2 Length times width. Divide by 2
0 Zero
The area of a triangle is (1/2) x base x height. The height is perpendicular to the base. In this case, you can take the 10 cm as the base, and calculate the height with Pythagoras' formula. If you split the base in half now you have two 5-12-13 right triangles, so the height is 12 cm and the area is (1/2)*(10cm)*(12cm) = 60 cm2
The hypotenuse of a right triangle with sides of 9 feet and 13 feet is: 15.81 feet
half of the product of these two sides ie (6 x 13)/2 ie 39
Area = 1/2*13*height = 104 Multiply both sides by 2: 13*height = 208 Divide both sides by 13: height = 16 inches Check: 1/2*13*16 = 104 square inches
Yes. The triangle with sides 7 cm, 8 cm, 13 cm is obtuse (the angle opposite the side of 13 cm is 120o) and scalene as none of the sides are equal.
You haven't given the units (inches or centimeters or what?) Anyway the hypotenuse is irrelevant all you need to find the area of a right angle triangle is the length of the other two sides. The formula is 1/2(W x H) = A. Which means half the width x the height gives you the area. In this case the width is 5 and the height is 12 which multiplied together gives 60 (the area of a rectangle of 5 x 12). You then need to half it to find the area of the right angle triangle and the answer is 30. Now you just need to know the units.
To calculate the area of a triangle with side lengths of 11cm, 8cm, and 7cm, we first need to determine the semi-perimeter of the triangle. The semi-perimeter (s) is calculated by adding all three sides together and dividing by 2, so s = (11 + 8 + 7) / 2 = 13 cm. Next, we can use Heron's formula to find the area of the triangle, which is given by the formula: Area = √[s(s-a)(s-b)(s-c)], where a, b, and c are the side lengths. Plugging in the values, we get Area = √[13(13-11)(13-8)(13-7)] = √[1325*6] = √780 ≈ 27.93 cm².
The area of triangle is : 78.0
Yes they could. The only requirement is that if you add any two sides together they are longer than the third. 19 + 13 > 14; 19 + 14 > 13, and 13 + 14 > 19, so those sides can make a triangle.