Lateral area: Twice the side of the square times the slant height. Surface area: The side of the square squared plus twice the side of the square times the slant height. a=side of square b=slant height L.A.=2(ab) S.A.=(a)(a)+(2(ab))
7 inches
it couldn't be a rectangle it would be a square and it would =24
The total surface area of a cuboid with edges of length a, b and c units is 2*(ab + bc + ca) square units.
Let ABCD be a rectangleAB = CD = 9 ftBC = DA(AB)x(BC) = 54 ftBC = 54/(AB) = 54/9 = 6 ftperimeter = (AB)+(BC)+(CD)+(DA) = 2(AB)+2(BC) = 2x9+2x6 = 30 ft
Lateral area: Twice the side of the square times the slant height. Surface area: The side of the square squared plus twice the side of the square times the slant height. a=side of square b=slant height L.A.=2(ab) S.A.=(a)(a)+(2(ab))
7 inches
Area = 10 sq cm
it couldn't be a rectangle it would be a square and it would =24
With sides of length A, B and C units, the total surface area is 2*(AB + BC + CA) square units.
Find ab
(ab) raised to 1/2 power
The total surface area of a cuboid with edges of length a, b and c units is 2*(ab + bc + ca) square units.
a square is ab square
AB can be found by using the distance formula, which is the square root of (x2-x1)^2 + (y2-y1)^2. In this case, AB= the square root of (-2-(-8))^2 + (-4-(-4))^2 which AB= the square root of 64 + 0 which AB=8.
Let ABCD be a rectangleAB = CD = 9 ftBC = DA(AB)x(BC) = 54 ftBC = 54/(AB) = 54/9 = 6 ftperimeter = (AB)+(BC)+(CD)+(DA) = 2(AB)+2(BC) = 2x9+2x6 = 30 ft
Using trigonometry the area of the given quadrilateral works out as 0.305 square cm