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If the median to a side of a triangle is also an altitude to that side then the triangle is isosceles How do you write this Proof?
Let the triangle be ABC and suppose the median AD is also an altitude.AD is a median, therefore BD = CDAD is an altitude, therefore angle ADB = angle ADC = 90 degreesThen, in triangles ABD and ACD,AD is common,angle ADB = angle ADCand BD = CDTherefore the two triangles are congruent (SAS).And therefore AB = AC, that is, the triangle is isosceles.
What is the proof that equiangular triangle is also called equilateral triangle?
Label the triangle ABC. Draw the bisector of angle A to meet BC at D. Then in triangles ABD and ACD, angle ABD = angle ACD (equiangular triangle) angle BAD = angle CAD (AD is angle bisector) so angle ADB = angle ACD (third angle of triangles). Also AD is common. So, by ASA, triangle ABD is congruent to triangle ACD and therefore AB = AC. By drawing the bisector of angle B, it can be shown that AB = BC. Therefore, AB = BC = AC ie the triangle is equilateral.
What is the area of the quadrilateral ABCD when AB is 0.38cm BC is 0.69cm and AD is 0.42cm with angles ABC 109 degrees and BAD 123 degrees?
Form two triangles from diagonal A to C and by finding the areas of each triangle they will add up to 0.305 square cm rounded to three decimal places.
How many medians are needed to find the centroid of a triangle?
Two. However, you can actually do it with just one. Consider the median AD of triangle ABC. Then the point G, 2/3 of the way from A to D, is the centroid. This process (2/3 of the way from the vertex to the opposite side) can be applied to any median.
Her original design for the ad is 6 inches wide and 4.5 inches tall but the space available is only 4 18 inches wide. If she shrinks the design to fit how tall will the ad be?
It will be 4.18 by 3.14 inches, approx.
