The sum of the first 40 whole numbers is 780.
The average of a series of numbers is their sum divided by however many numbers there are: in this case you would calculate: (16 + 40) / 2 =56 / 2 =28 Therefore the average of 16 and 40 is 28.
11
6 + 10 + 8 + 7 + 9= 40----------you have 5 integers, so......40/5= 8=====the arithmetic average, or the mean of these numbers
Let the two numbers be x and y. Let suppose that the average of two numbers is 20. Then,x + y = 40 and 40/GCF = 5, where GCF = 40/5 = 8Since LCM is 48 and GCF is 8, the numbers are 16 and 24, whose average is 20 is true.
The sum of the first 40 whole numbers is 780.
The sum of the first 40 odd numbers is 1,600.
The sum of the first 40 even numbers is 1,640.
The average of five numbers whose sum is 200 will always be 40, no matter which numbers you choose. When finding an average, you add up the numbers (find the sum of the set), then divide by the number of terms. In this case, the sum will always be 200, and there will always be five terms. This will always result in an average of 40. Ex/ 1 + 2 + 3 + 4 + 190 = 200 200 / 5 = 40 40 + 40 + 80 + 24 + 16 = 200 200 / 5 = 40
None.
The average of 31,52and 40 is 41 because you add all the numbers and then didvde it by 3 because there are 3 numbers there and you get 41.
Sum of numbers = 40 Count of numbers = 4 Average = Sum/Count = 40/4 = 10
The average of a series of numbers is their sum divided by however many numbers there are: in this case you would calculate: (16 + 40) / 2 =56 / 2 =28 Therefore the average of 16 and 40 is 28.
11
In total, we are changing the sum of the 9 numbers by 1 + 2 + ... + 9 = 9 x 10 / 2 = 45, so each of the numbers is increased by, on average, 45/9=5. If the old average was 40, the new one is 40 + <the average amount each number was increased by> = 40 + 5 = 45.
6 + 10 + 8 + 7 + 9= 40----------you have 5 integers, so......40/5= 8=====the arithmetic average, or the mean of these numbers
45