What is the center of the circle given by the equation (x - 3)2 (y - 9)2 16?

Answer 1

Well, honey, the center of that circle is simply the point (3, 9). You see, the equation you provided is in the form (x - h)² + (y - k)² = r², where (h, k) is the center of the circle. So, in this case, the center is at (3, 9). That's all there is to it, sugar.

Answer 2

Oh, dude, the center of a circle is just the point (h, k) in the equation (x - h)^2 + (y - k)^2 = r^2, where (h, k) is the center of the circle. So, in this case, the center is at (3, 9) because the equation is already in the form (x - h)^2 + (y - k)^2 = r^2. Easy peasy lemon squeezy!

Answer 3

To find the center of the circle given by the equation (x - 3)^2 + (y - 9)^2 = 16, we need to rewrite the equation in standard form, which is (x - h)^2 + (y - k)^2 = r^2, where (h, k) is the center of the circle and r is the radius. Comparing the given equation with the standard form, we can see that the center of the circle is at (3, 9).