There is a better chance of rolling a 7 because there are more combinations of numbers on a pair of dice that add to 7 (the probability of rolling a 7 is 6/36 vs a 9 which is 4/36).1 2 3 4 5 6+-------------------1 | 2 3 4 5 6 72 | 3 4 5 6 7 83 | 4 5 6 7 8 94 | 5 6 7 8 9 105 | 6 7 8 9 10 116 | 7 8 9 10 11 12
1/6
The chance is 9%
Each die has a 5/6 chance independent of the other.
It is 6*6-5 = 6-4 = 1/1296 = 0.00077 (approx).
There is a better chance of rolling a 7 because there are more combinations of numbers on a pair of dice that add to 7 (the probability of rolling a 7 is 6/36 vs a 9 which is 4/36).1 2 3 4 5 6+-------------------1 | 2 3 4 5 6 72 | 3 4 5 6 7 83 | 4 5 6 7 8 94 | 5 6 7 8 9 105 | 6 7 8 9 10 116 | 7 8 9 10 11 12
The chance of rolling a certain number on a dice is 1/6, so the chance of rolling a 4 OR 5is 2/6. But if you have two dice you have the most chance of rolling a seven (6/36 or 1/6)
1/6
The chance is 9%
In craps, the chance for rolling a 7 never changes. First roll, tenth roll - doesn't matter. The chance is always 6 out of 36 (or roughly 17%). The chance of rolling a 6 is always 5 out of 36 (or 20%). The chance of rolling an 8 is always 5 out of 36 (or 20%). The chance of hitting either a 6 or an 8 before hitting a 7 would be 10 to 6 (with the favor going towards hitting either the 6 or 8).
The chance of rolling it each time is (1/6). So the chance of rolling it 4 times in a row is(1/6) x (1/6) x (1/6) x (1/6) = (1/1296) = 0.0007716 = 0.0772 % (rounded)The chance of rolling it each time is the same. It's not affected by what came before,since dice have no memory.
Each die has a 5/6 chance independent of the other.
it is all about chance my dear girl/boy but most likely a 1.98007657 chance
The problem can be split into two parts, rolling a 12, or rolling a 4 or less. This can be further broken down to rolling a 2, rolling a 3, rolling a 4, or rolling a 12. P(rolling 4 or less, or 12) = P(rolling 4 or less) + P(rolling 12) = P(rolling a 2) + P(rolling a 3) + P(rolling a 4) + P(rolling a 12) = 1/36 + 2/36 + 3/36 + 1/36 = 7/36
1/6+1/6=1/3
It is 6*6-5 = 6-4 = 1/1296 = 0.00077 (approx).
There are 21 different combinations of two dice. Three of them total 7 (3 + 4, 2 + 5, 1 + 6), so if you have two 'fair' dice, you have a 1 in 3 chance of totalling 7.