If the question refers to a square, then circumference = 4d, where d is the length of a side.
20 = 4d therefore d = 20/4 = 5 ft.
If the question refers to a circle with a circumference (C) of 20', then C = 2πr, where r is the radius of the circle.
20 = 2πr therefore r = 20 ÷ 2π = 3.18 ft
If the question refers to the circumference of a circle with radius 20', then
C = 2π x 20 = 40π = 125.66 ft
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circumference = π x diameter => diameter = circumference ÷ π ~= 20ft ÷ 3.14 ~= 6.37 ft
The circumference of a circular pool can be calculated using the formula (C = 2\pi r), where (r) is the radius. For a 20 ft diameter pool, the radius is 10 ft. Therefore, the circumference is (C = 2\pi(10) \approx 62.83) ft.
If the circle is 20 ft radius, the area is π·20² = 1256.637 ft² If the circle is 20 ft diameter, the area is π·(20/2)² = 314.1593 ft² If the circle is 20 ft circumference, the are is π·(20/2π)² = 63.66198 ft²
The way this question is worded indicates that the circumference is 2 ft.
If its diameter is 43 ft then its circumference is pi*43 = 135.088 ft to 3 dp