If the question refers to a square, then circumference = 4d, where d is the length of a side.
20 = 4d therefore d = 20/4 = 5 ft.
If the question refers to a circle with a circumference (C) of 20', then C = 2πr, where r is the radius of the circle.
20 = 2πr therefore r = 20 ÷ 2π = 3.18 ft
If the question refers to the circumference of a circle with radius 20', then
C = 2π x 20 = 40π = 125.66 ft
circumference = π x diameter => diameter = circumference ÷ π ~= 20ft ÷ 3.14 ~= 6.37 ft
If the circle is 20 ft radius, the area is π·20² = 1256.637 ft² If the circle is 20 ft diameter, the area is π·(20/2)² = 314.1593 ft² If the circle is 20 ft circumference, the are is π·(20/2π)² = 63.66198 ft²
The way this question is worded indicates that the circumference is 2 ft.
If its diameter is 43 ft then its circumference is pi*43 = 135.088 ft to 3 dp
The circumference of a circle is the same as the perimeter of a circle, so the perimeter and circumference would both be 3 ft.
That depends on what you mean by a "20 ft semicircle".A semi-circle is a half circle.A 20 ft circle could be:A circle of diameter 20 ftThe perimeter of the semicircle is half the circumference plus the diameter → perimeter = 1/2π 20 ft + 20 ft= 10π + 20 ft≈ 51.42 ftA circle of radius 20 ftThe perimeter of the semicircle is half the circumference plus double the radius → perimeter = 1/2 2π 20 ft + 2 x 20 ft= 20π + 40 ft≈ 102.08 ftA circle of circumference 20 ftThe perimeter of the semicircle is half the circumference plus the diameter → perimeter = 1/2 20 ft + 20 ft ÷ π= 10 ft + 20/π ft≈ 16.37 ftHowever, if a 20 ft circle is a circle with a circumference (= perimeter) of 20 ft then a 20 ft semi-circle could be a semicircle with a perimeter of 20 ft→ perimeter = 20 ft
circumference = π x diameter => diameter = circumference ÷ π ~= 20ft ÷ 3.14 ~= 6.37 ft
If the circle is 20 ft radius, the area is π·20² = 1256.637 ft² If the circle is 20 ft diameter, the area is π·(20/2)² = 314.1593 ft² If the circle is 20 ft circumference, the are is π·(20/2π)² = 63.66198 ft²
That my friend would be 62.8
I'm guessing you mean 20 ft. circumference? With a 20' circumference, here's the math. C=20; C(r)=2*[pi]*r; 2*[pi]*r=20; r=10/[pi] A(r)=r2*[pi]; A=(10/[pi])2*[pi]; A= about 31.831 sq. ft.
There are 20 linear feet across the diameter; and 20π ≈ 62.83 linear feet around the circumference.
The circumference is 50π ft or 157.08 ft.
The circumference of a 30 ft circle is: 94.2 feet.
The circumference of an 8 ft circle is: 25.1 feet.
The way this question is worded indicates that the circumference is 2 ft.
Circumference of a circle = 2piradius or pi*diameter
If its diameter is 43 ft then its circumference is pi*43 = 135.088 ft to 3 dp