5,17,29,41,53,65,?
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16
They are: 17+12 = 29 and 17-12 = 5
Arithmetic
The given sequence is an arithmetic sequence where each term increases by 4. The first term (a) is 13, and the common difference (d) is 4. The nth term can be found using the formula: ( a_n = a + (n-1)d ). Therefore, the nth term is ( a_n = 13 + (n-1) \cdot 4 = 4n + 9 ).
To find the larger number, we can add the difference of 12 to the smaller number of 17. This gives us 17 + 12 = 29. Therefore, the larger number is 29.